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shusha [124]
1 year ago
5

4

Mathematics
1 answer:
Natali [406]1 year ago
8 0

The ratio of the area of ∆ABC to the area of ∆DEF is; 1:100.

<h3>What is the ratio of the area of ∆ABC to the area of ∆DEF?</h3>

Since, a major criterion for similarity and congruence of triangles is that the ratio of corresponding sides are equal.

On this note, since the task content suggest that the ratio of the perimeters is; 1:10, it follows from conventional mathematics that the ratio of their areas is given as; 1²:10²; 1:100.

Read more on congruent triangles;

brainly.com/question/9217675

#SPJ1

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Step-by-step explanation:

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3 years ago
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5 0
3 years ago
A)-1 <br> B) 1<br> C) 2<br> D) -1/2
AURORKA [14]

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7 0
3 years ago
<img src="https://tex.z-dn.net/?f=Simplify%3A%20%20%5Cfrac%7B%20%7Bx%7D%5E%7Ba%20%2B%20b%7D%20.%20%7Bx%7D%5E%7Bb%20%2B%20c%7D%20
kozerog [31]

Step-by-step explanation:

\bf \underline{Solution-} \\

We have to simplify the given expression.

\rm =  \dfrac{ {x}^{a + b} \cdot {x}^{b + c} \cdot {x}^{c + a}  }{ {x}^{a} \cdot {x}^{b} \cdot {x}^{c} }

We know that:

\rm \longmapsto {x}^{a} \times  {x}^{b}  =  {x}^{a + b}

\rm \longmapsto \dfrac{ {x}^{a} }{ {x}^{b} } =  {x}^{a -  b}

Therefore, we get:

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\rm =  \dfrac{ {x}^{2(a + b+ c)}}{ {x}^{a + b + c} }

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7 0
2 years ago
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leonid [27]

Answer:

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