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levacccp [35]
3 years ago
12

What is the density of 35 ml of a liquid that has a mass of 28.7 g?

Chemistry
2 answers:
omeli [17]3 years ago
4 0
Hey there!:

Mass = 28.7 g

Volume = 35 mL

Therefore:

D = m / V

D = 28.7 / 35

D = 0.82 g/mL
Nadya [2.5K]3 years ago
3 0

Answer: The density of the liquid will be 0.82 g/ml.

Explanation:

Density is defined as the mass contained per unit volume.

Density=\frac{mass}{Volume}

Given : Mass of liquid = 28.7 grams

Volume of liquid  = 35 ml

Putting in the values we get:

Density=\frac{28.7g}{35ml}=0.82g/ml

Thus density of the liquid will be 0.82g/ml

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For the following reaction, 9.30 grams of glucose (C6H12O6) are allowed to react with 13.8 grams of oxygen gas. glucose (C6H12O6
amid [387]

Answer:

13.7 g of CO₂

Limiting reactant:  C₆H₁₂O₆

3.81 g of O₂

Explanation:

We convert the mass of the reactants to moles, in order to find out the limiting reactant and the excess reagent

9.30 g / 180 g/mol = 0.052 moles of glucose

13.8 g / 32 g/mol = 0.431 moles of oxygen

The equation is:  C₆H₁₂O₆(s) + 6O₂ (g) → 6CO₂ (g) + 6H₂O (l)

Ratio is 1:6. Let's consider this rule of three:

1 mol of glucose reacts with 6 moles of oxygen

Then, 0.052 moles of glucose must react with (0.052 . 6) /1 = 0.312 moles

We have 0.431 moles of oxygen and we only need 0.312 moles. This means that an amount of oxygen still remains after the reaction is complete:

0.431 - 0.312 = 0.119 moles. We convert the moles to mass:

0.119 mol . 32 g / 1mol = 3.81 g

In conclussion, the limiting reactant is the glucose.

6 moles of oxygen react with 1 mol of glucose

0.431 moles of O₂ will react with (0.431 . 1) /6 = 0.072 moles of glucose

We only have 0.052 moles, so it is ok to say, that glucose is the limiting cause we do not have enough glucose.

Let's verify, the maximum amount of carbon dioxide that can be formed:

1 mol of glucose can produce 6 moles of CO₂

Therefore 0.052 moles of glucose will produce (0.052 . 6) /1 = 0.312 moles

We convert the moles to mass → 0.312 mol . 44 g /1 mol = 13.7 g

6 0
3 years ago
How many grams of water can be formed from the reaction of 8.76 grams of H2 with 10.5 liters of O2 (at STP) according to the bal
Kisachek [45]

Answer:

16.9g of H₂O can be formed

Explanation:

Based on the chemical reaction, 2 moles of H₂ react per mole of O₂. To anser this question we must find limiting reactant converting the mass and volume of each reactant to moles:

<em>Moles H₂ -Molar mass: 2.016g/mol-:</em>

8.76g * (1mol / 2.016g) = 4.345 moles

<em>Moles O₂:</em>

PV = nRT

PV/RT = n

P = 1atm at STP

V = 10.5L

R = 0.082atmL/molK

T = 273.15K at STP

n = 1atm*10.5L / 0.082atmL/molK*273.15K

n = 0.469 moles of oxygen

For a complete reaction of 4.345 moles moles of hydrogen are required:

4.345 moles H2 * (1mol O2 / 2mol H2) = 2.173 moles of O2 are required. As there are just 0.469 moles, Oxygen is limiting reactant

Now, 1 mole of O2 produce 2 moles of H2O. 0.469 moles will produce:

0.469 moles O₂ * (2 moles H₂O / 1mol O₂) = 0.938 moles H₂O.

The mass is -Molar mas H₂O = 18.01g/mol-:

0.938 moles * (18.01g/mol) =

<h3>16.9g of H₂O can be formed</h3>
8 0
3 years ago
Why is air considered a mixture not a compound?
blondinia [14]
<span>The best reason I can think of for why we believe that air is a mixture is that freezing air slowly yields different liquids at different temperatures. Liquid nitrogen has a different boiling point than liquid oxygen. They also freeze at different temperatures. If air were only 1 compound, then air in its entirety would have a single boiling point and a single freezing point. </span>
8 0
3 years ago
The crystallization of salt from evaporating seawater a. is an example of precipitation from a solution. b. is, in mineralogic t
Ad libitum [116K]

Answer:

is an example of precipitation from a solution.

Explanation:

3 0
3 years ago
A 76.00-pound flask of mercury costs $151.50. The density of mercury is 13.534 g/cm3.
Agata [3.3K]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Please see below solution:

1 lb Hg x (151.50/76 lb) = cost of 1 lb. 
<span>cost 1 lb x (1g/453.6 g) = cost of 1 g.</span>
8 0
3 years ago
Read 2 more answers
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