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3 years ago

Which characteristic best identifies an Arrhenius base

2 answers:

8 0

<span>Arrhenius base, such as NaOH(aq), produce hydroxide ions when dissolved in water. According to Arrhenius, base are compounds or ions that releases hydroxide (OH-) ions in its aqueous form which is true for NaOH.</span>

Jlenok [28]3 years ago

7 0

For edgeuity, I think that the answer is C) it must generate hydroxide ions in water

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How many electrons will metals generally have in their outer shell

Goshia [24]

Answer:

1 - 3

Explanation:

- Look to see where metals are on the periodic table then look at what group they are in. The group tells you the number of valence electrons. Ex. 1A has one valence electron.

- Hope this helped! If you need a further explanation please let me know.

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3 years ago

How do humans depend on the ocean

slamgirl [31]

Answer:

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3 years ago

What is FeBr3 compound name?

inessss [21]

Iron bromide. Iron bromide (FeBr3)

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3 years ago

Read 2 more answers

What type of bond is NH3?<br> Ionic, Polar covalent, nonpolar covalent, or metallic

laila [671]

Polar covalent because it is 2 nonmetals and the molecule has a net dipole movement.

8 0

3 years ago

3. The following data of decomposition reaction of thionyl chloride (SO2Cl2) were collected at a certain temperature and the con

KonstantinChe [14]

Answer:

a) First-order.

b) 0.013 min⁻¹

c) 53.3 min.

d) 0.0142M

Explanation:

Hello,

In this case, on the attached document, we can notice the corresponding plot for each possible order of reaction. Thus, we should remember that in zeroth-order we plot the concentration of the reactant (SO2Cl2 ) versus the time, in first-order the natural logarithm of the concentration of the reactant (SO2Cl2 ) versus the time and in second-order reactions the inverse of the concentration of the reactant (SO2Cl2 ) versus the time.

a) In such a way, we realize the best fit is exhibited by the first-order model which shows a straight line (R=1) which has a slope of -0.0013 and an intercept of -2.3025 (natural logarithm of 0.1 which corresponds to the initial concentration). Therefore, the reaction has a first-order kinetics.

b) Since the slope is -0.0013 (take two random values), the rate constant is 0.013 min⁻¹:

$m=\frac{ln(0.0768)-ln(0.0876)}{200min-100min} =-0.0013min^{-1}$

c) Half life for first-order kinetics is computed by:

$t_{1/2}=\frac{ln(2)}{k}=\frac{ln(2)}{0.013min^{-1}} =53.3min$

d) Here, we compute the concentration via the integrated rate law once 1500 minutes have passed:

$C=C_0exp(-kt)=0.1Mexp(-0.013min^{-1}*1500min)\\\\C=0.0142M$

Best regards.

6 0

3 years ago