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vaieri [72.5K]
3 years ago
11

Which characteristic best identifies an Arrhenius base

Chemistry
2 answers:
skad [1K]3 years ago
8 0

<span>Arrhenius base, such as NaOH(aq), produce hydroxide ions when dissolved in water. According to Arrhenius, base are compounds or ions that releases hydroxide (OH-) ions in its aqueous form which is true for NaOH.</span>

Jlenok [28]3 years ago
7 0

For edgeuity, I think that the answer is C) it must generate hydroxide ions in water

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This equation is balanced
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El ácido sulfúrico H2SO4 es uno de los compuestos que se utiliza para la producción de fertilizantes como el nitrosulfato amónic
Serjik [45]

Explanation:

12 hours ago

El ácido sulfúrico H2SO4 es uno de los compuestos que se utiliza para la producción de fertilizantes como el nitrosulfato amónico. Si disponemos de 8 mL de H2SO4 al 37 %P/P (d=1,26 g /mL), los cuales se disolvieron hasta alcanzar un volumen de solución de 400 mL, con una densidad de 1,08 g/mL. (La densidad del soluto es corresponde a 1,83 g/cm³)

5 0
3 years ago
The change in speed that could occur in 4 seconds in an object with an acceleration of 6 m/s/s.
bazaltina [42]

Answer:

24m/s

Explanation:

a=change of v/change of t

6m/s^2=v/4s

multiply both sides by 4s

v=24m/s

4 0
3 years ago
If 40.0 mL of a calcium nitrate solution reacts with excess potassium carbonate to yield 0.524 grams of a precipitate, what is t
tankabanditka [31]

Answer : The molarity of calcium ion on the original solution is, 0.131 M

Explanation :

The balanced chemical reaction is:

Ca(NO_3)_2+K_2CO_3\rightarrow CaCO_3+3KNO_3

When calcium nitrate react with potassium carbonate to give calcium carbonate as a precipitate and potassium nitrate.

First we have to calculate the moles of CaCO_3

\text{Moles of }CaCO_3=\frac{\text{Mass of }CaCO_3}{\text{Molar mass of }CaCO_3}

Given:

Mass of CaCO_3 = 0.524 g

Molar mass of CaCO_3 = 100 g/mol

\text{Moles of }CaCO_3=\frac{0.524}{100g/mol}=0.00524mol

Now we have to calculate the concentration of CaCO_3

\text{Concentration of }CaCO_3=\frac{\text{Moles of }CaCO_3}{\text{Volume of solution}}=\frac{0.00524mol}{0.040L}=0.131M

Now we have to calculate the concentration of calcium ion.

As, calcium carbonate dissociate to give calcium ion and carbonate ion.

CaCO_3\rightarrow Ca^{2+}+CO_3^{2-}

So,

Concentration of calcium ion = Concentration of CaCO_3 = 0.131 M

Thus, the concentration or molarity of calcium ion on the original solution is, 0.131 M

4 0
3 years ago
1. Define each of the ways that matter is measured:<br> a. Mass-<br><br> b. Volume -
adoni [48]

Answer:

Explanation:

Mass is how much an object weighs . Volume is the amount of space the object takes up

4 0
3 years ago
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