35g Mg x 1mol / 24g = 840 mol
I am so sorry I do not know but I need to answer a question in order to ask one I hope u pass:))
The percentage composition of CF4 is %C = 13.64% and %F = 86.36%
The solution are as follows:
Molar mass of CF4 = 88
<span>molar mass of C = 12 </span>
<span>molar mass of F = 4x19 = 76 </span>
<span>% C = 12/88 x 100 = 13.64% </span>
<span>% F = 76/88 x 100 = 86.36%</span>
Elements in the same group have similar properties
