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lawyer [7]
3 years ago
9

Which of the following represents the correct ranking in terms of increasing boiling point? A. n-butane < 1-butanol < diet

hyl ether < 2-butanone B. n-butane < 2-butanone < diethyl ether < 1-butanol C. 2-butanone < n-butane < diethyl ether < 1-butanol D. n-butane < diethyl ether < 1-butanol < 2-butanone E. n-butane < diethyl ether < 2-butanone < 1-butanol
Chemistry
1 answer:
bonufazy [111]3 years ago
6 0

Answer:

The answer to your question is: letter E

Explanation:

Normally, the correct order of boiling points is:

                     Alcohols > Ketones > Ether > Alkane

Then

A. n-butane < 1-butanol < diethyl ether < 2-butanone

B. n-butane < 2-butanone < diethyl ether < 1-butanol

C. 2-butanone < n-butane < diethyl ether < 1-butanol

D. n-butane < diethyl ether < 1-butanol < 2-butanone

E. n-butane < diethyl ether < 2-butanone < 1-butanol

     (- 1°C)     <    34.6°C         <  79.64°C      <  117.7°C

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What is the difference between interpreting and analyzing
Basile [38]

Answer:

 Analizar da a entender que se aprecia algo detenidamente para buscar una respuesta a una incógnita.

Interpretar da a entender que se da mención de x cosa de acuerdo a lo que uno sabe de dicha cosa.

4 0
3 years ago
What properties of matter are intensive independent of their size
Paha777 [63]

Answer:

temperature, refractive index, density, and hardness of an object

Explanation:

it is a bulk property, meaning that it is a physical property of a system that does not depend on the system size or the amount of material in the system

8 0
3 years ago
I need help with that question please help me I really need it so much I been struggling and stressing a lot please it is due to
s2008m [1.1K]

Answer:

5000*C abd 1.5 million atmospheres

6 0
3 years ago
B. The equilibrium constant for the reaction 2H2(g) + S2(g) 2H2S(g) is Keq = . (3 points)
eimsori [14]

Answer:

i. Keq=4157.99.

ii. More hydrogen sulfide will be produced.

Explanation:

Hello,

i. In this case, for the concentrations at equilibrium on the given chemical reaction, the equilibrium constant results:

Keq=\frac{[H_2S]^2}{[H_2]^2[S_2]} =\frac{(0.97M)^2}{(0.051M)^2(0.087)} =4157.99

ii. Now, by means of the Le Chatelier's principle, the addition of a reactant shifts the reaction towards products, it means that more hydrogen sulfide will be produced in order to reach equilibrium.

Best regards.

4 0
3 years ago
25 g of NH, is mixed with 4 moles of O, in the given reaction:
FromTheMoon [43]

Answer:

a. NH3 is limiting reactant.

b. 44g of NO

c. 40g of H2O

Explanation:

Based on the reaction:

4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(l)

4 moles of ammonia reacts with 5 moles of oxygen to produces 4 moles of NO and 6 moles of water.

To find limiting reactant we need to find the moles of each reactant and using the balanced equation find which reactant will be ended first. Then, with limiting reactant we can find the moles of each reactant and its mass:

<em>a. </em><em>Moles NH3 -Molar mass. 17.031g/mol-</em>

25g NH3*(1mol/17.031g) = 1.47moles NH3

Moles O2 = 4 moles

For a complete reaction of 4 moles of O2 are required:

4mol O2 * (4mol NH3 / 5mol O2) = 3.2 moles of NH3.

As there are just 1.47 moles, NH3 is limiting reactant

b. Moles NO:

1.47moles NH3 * (4mol NO/4mol NH3) = 1.47mol NO

Mass NO -Molar mass: 30.01g/mol-

1.47mol NO * (30.01g/mol) = 44g of NO

c. Moles H2O:

1.47moles NH3 * (6mol H2O/4mol NH3) = 2.205mol H2O

Mass H2O -Molar mass: 18.01g/mol-

2.205mol H2O * (18.01g/mol) = 40g of H2O

3 0
3 years ago
Read 2 more answers
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