In the manufacture of steel, pure oxygen is blown through molten iron to remove some of the carbon impurity. if the combustion o
f carbon is efficient, carbon dioxide (density = 1.80 g/l) is produced. incomplete combustion produces the poisonous gas carbon monoxide (density - 1.15 g/l) and should be avoided. if you measure a gas density of 1.77 g/l, what can you conclude?
In the extraction process of steel, one of the step is purification of the iron used to make the steel. In which pure oxygen is blown on the steel at high temperature so that the carbon percentage present in the steel can be thrown out in the form of gas. The process occurs at high temperature which is called combustion process. The reaction occurs can be shown as- C(s)+→C (g) + CO (g). In presence of excess oxygen, the produced carbon mono oxide (CO) converts to carbon di-oxide. The reaction is CO(g) + (g) → C (g). From the density of the evolved gas one could identify the gas. If the gas density is 1.77g/L which is very close to the standard density of C i.e. 1.80g/L, the gas is carbon dioxide only.
We can conclude that the gas evolved was carbon dioxide.
Explanation:
On an efficient combustion that is on complete combustion of carbon, carbon dioxide is produced.
(Complete combustion)
But during incomplete combustion of carbon results in formation of carbon monoxide (poisons gas).
(Incomplete combustion)
Theoretical value density of carbon dioxide = 1.80 g/L
Theoretical value density of carbon monoxide = 1.15 g/L
Experimental measured density of the gas = 1.77 g/L
1.77 g/L ≈ 1.80 g/L
Since, the experimental measured density of the gas is more closer to theoretical value of density of carbon dioxide from which we can conclude that 'the gas evolved after the combustion of carbon impurity was carbon dioxide'.
Because the two particles have an equal charge, the charges will cancel out and give the atom an overall charge of 0. So, if at atom has 35 protons in the nucleus, we could expect it to have 35 electrons orbiting that nucleus.
The fourth period contains 18 elements, beginning with potassium and ending with krypton. As a rule, period 4 elements fill their 4s shells first, then their 3d and 4p shells, in that order; however, there are exceptions, such as chromium.
actually word equation has the names and we need to write molecular formula in chemical eqn. so I don't think there is sort of trick.You just need to memorise the molecular formula of chemicals.