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Temka [501]
2 years ago
5

Sophia for the exponential function f left parenthesis x right parenthesis equals 5 times 2 to the power of x, what is the value

of f left parenthesis 3 right parenthesis?
Mathematics
1 answer:
vekshin12 years ago
6 0

The value of f left parenthesis 3 right parenthesis is 45.

According to the statement

We have given that the F(x) = 5(x)^2

and we have to find the value when Sophia have a 3 right parenthesis.

So, Parenthesis are used in mathematical expressions to denote modifications to normal order of operations.

And now we have to find the value for 3 right parenthesis

And for this purpose we have to put the value X= 3 in the f(x) then

F(x) = 5(x)^2

F(3) = 5(3)^2

F(3) = 5*9

F(3) = 45.

here the value of 3 right parenthesis is 45.

So, The value of f left parenthesis 3 right parenthesis is 45.

Learn more about PARENTHESIS here brainly.com/question/1473593

#SPJ4

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Answer:

Max = (6,0); min = (-2, 4)  

Step-by-step explanation:

1. Summarize the constraints

\text{Constraints} = \begin{cases}(a)\qquad 2x - y  & \leq 12\\(b)\qquad 4x+ 2y & \geq 0\\(c) \qquad x + 2y  & \leq 6\\ \end{cases}

2. Optimization equation

z = 5x + 2y

3. Graph the constraints to identify the feasible region

See the figure below.

The "TRUE" regions for each graph are the shaded areas to the side of the line indicated by the arrows.

The "feasibility region" is the dark green area where all three areas overlap and all three conditions are satisfied.

5. Determine the points of intersection among the constraints  

(i) Constraints (a) and (b)

\begin{array}{rcr}2x - y  & = & 12\\4x + 2y & = & 0\\4x - 2y & = & 24\\8x&=&24\\x & = & \mathbf{3}\\6 - y & = & 12\\-y & = &6\\y & = & \mathbf{-6}\\\end{array}\\

The lines intersect at (3,-6).

(ii) Constraints (a) and (c)

\begin{array}{rcr}2x - y  & = & 12\\x + 2y & = & 6\\4x - 2y & = &24\\5x & = & 30\\x & = & \mathbf{6}\\6 + 2y & = & 6\\2y & = &0\\y & = & \mathbf{0}\\\end{array}

The lines intersect at (6,0).

(iii) Constraints (b) and (c)

\begin{array}{rcr}4x+ 2y &= & 0\\x + 2y  &=& 6\\3x & = &  -6\\x & = & \mathbf{-2}\\-2 +2y & = & 6\\2y & = &8\\y & = & \mathbf{4}\\\end{array}

The lines intersect at (-2,4).

6. Determine the x- and y-intercepts of the feasible region

The five black dots at (3,-6), (6,0), and (-2,4) are the vertices of the polygon that represents the feasible region.

Each vertex is a possible maximum or minimum of z.  

7. Calculate the maxima and minima

Calculate z at each of the vertices.

(i) At (-2,4)

z = 5x + 2y = 5(-2) + 2(4) = -10 + 8 = 2

(ii) At (3,-6)

z =  5(3) + 2(-6) = 15 - 12 = 3

(iii) At (6,0)

z = 5(6)+ 2(0) = 30 + 0 = 30

The maximum of z occurs at (6,0).

The minimum of z occurs at (-2, 4).

 

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