Answer:
it would be 6 and 6 since it states equal distance and it also says a few forward and a few backward. It makes it sound like this was an equal amount each way
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given
Required
Determine the 10th term
Using binomial expansion, we have:
For, the 10th term. n = 9
So, we have:
Apply combination formula
Hence, the 10th term is
Answer:
Height+surface area of the bottom circles*2
Step-by-step explanation:
If the height was 3 and the surface areas of the circles were 6, you would end up with a surface area of 15
First find the area of the sector, which includes the shaded region's area and the area of the triangle JKL. Let be the area of the sector. This area occurs in a fixed ratio with the area of the entire circle based on the measure of the central angle subtended by the arc LK:
To get the area of the shaded region, subtract from the area of the triangle.
The area of a triangle is 1/2 the base times the height. If we bisect the central angle with a line segment that meets the side KL at its midpoint, then we get a right triangle with hypotenuse 27 and one angle of measure 27º (half of the central angle). This triangle has base and height such that
So the right triangle has area approximately 1/2*12.258*24.057, or about 147.443. Triangle JKL is made up of two of these right triangles, so it has area of 294.887.
Subtracting this from gives an area of the shaded region of about 48.472, which we round up to 48.5.