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3 years ago

PLEASE HELP THIS TEST IS DUE IN TEN MINS

Physics

2 answers:

Sveta_85 [38]3 years ago

4 0

Answer:

A I hope you get it !!!!!!!

nekit [7.7K]3 years ago

3 0

Answer:

A. A statement of how the volume of a gas is related to its temperature.

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The overall charge of an ionic compound is ______________. a. always positive b. usually positive c. usually negative d. usually

telo118 [61]

Answer:

d. usually neutral

Explanation:

The overall charge of an ionic compound is usually neutral.

There is no net charge on the compound formed by an ionic bond due to the electrical stability that is derived from this bond association.

In an ionic bond, a metal transfers some of its electrons to a non-metal. The metal is electropositive and the non-metal is electronegative.

Therefore, the result is that two ions are produced which attracts each other with an electrostatic force.

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3 years ago

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DiKsa [7]

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3 years ago

A wire of length 6cm makes an angle of 20° with a 3 mT

Crazy boy [7]

Answer:

Approximately $7.3 \times 10^{-3}\; \rm A$ (approximately $7.3\; \rm mA$ ) assuming that the magnetic field and the wire are both horizontal.

Explanation:

Let $\theta$ denote the angle between the wire and the magnetic field.

Let $B$ denote the magnitude of the magnetic field.

Let $l$ denote the length of the wire.

Let $I$ denote the current in this wire.

The magnetic force on the wire would be:

$F = B \cdot l \cdot I \cdot \sin(\theta)$ .

Because of the $\sin(\theta)$ term, the magnetic force on the wire is maximized when the wire is perpendicular to the magnetic field (such that the angle between them is $90^\circ$ .)

In this question:

$\theta = 20^\circ$ (or, equivalently, $(\pi / 9)$ radians, if the calculator is in radian mode.)
$B = 3\; \rm mT = 3 \times 10^{-3}\; \rm T$ .
$l = 6\; \rm cm = 6 \times 10^{-2}\;\rm m$ .
$F = 1.5\times 10^{-4}\; \rm N$ .

Rearrange the equation $F = l \cdot I \cdot \sin(\theta)$ to find an expression for $I$ , the current in this wire.

$\begin{aligned} I &= \frac{F}{l \cdot \sin(\theta)} \\ &= \frac{3\times 10^{-3}\; \rm T}{6 \times 10^{-2}\; \rm m \times \sin \left(20^{\circ}\right)} \\ &\approx 7.3 \times 10^{-3}\; \rm A = 7.3 \; \rm mA\end{aligned}$ .