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Jobisdone [24]
2 years ago
10

In high-wind installations, if an old composition asphalt shingle roof is going to be replaced, the roofing contractor should __

_________ the existing shingles and underlayment.
Engineering
1 answer:
andrey2020 [161]2 years ago
8 0

In regards to high-wind installations, if an old composition asphalt shingle roof is going to be replaced, the roofing contractor should remove the existing shingles and underlayment.

<h3>What are High Wind installations?</h3>

High Wind is known to be a newly created installation techniques that is often used in the installation of offshore wind turbines and this is often done at  higher wind speeds.

Note that, In regards to high-wind installations, if an old composition asphalt shingle roof is going to be replaced, the roofing contractor should remove the existing shingles and underlayment.

Learn more about installations from

brainly.com/question/13093522

#SPJ1

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Unlike expendable molds, permanent molds do not collapse, so the mold must be opened before appreciable cooling contraction occu
Pani-rosa [81]

Answer: True

Explanation:

Permanent molds do not collapse, unlike expendable molds so the mold must be opened before appreciable cooling contraction occurs in order to prevent cracks from developing in the casting.

The metal casting becomes solid inside the mold after it has been poured. But during the process of manufacture, before the would cools any further, they usually remove the metal cast in order to stop excess contractions of the solid metal casting in the mold. This is done to prevent prevent cracks from developing in the casting since permanent mold do not collapse.

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3 years ago
Which of the following is a true statement about falling object safety?
Anastaziya [24]

Answer:

regregregrega

Explanation:

a

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3 years ago
2.13 LAB: Expression for calories burned during workout
katrin [286]

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3 years ago
You get invited to a party at a 1,200 sf apartment, where there are a total of 23 people. The apartment has ceilings that are 8
yawa3891 [41]

Answer:

concentration of air =  0.0000366 ppm is not sufficient to cause any eye irritation

Explanation:

Average amount of aldehyde generated by a cigarette = 1 mg = 10⁻⁶g

Room volume = Height * Base area

Room volume = 8ft * 1200 sq.ft = 9600 cubic feet

number of people in the room = 23

If 1 person smokes 2 cigarette in 1 hour,

23 people will smoke 23*2 cigarettes = 46 cigarettes in 1 hr

Mass of aldehyde generated by 1 cigarette = 10⁻⁶g

Mass of aldehyde generated by 46 cigarettes = 46 * 10⁻⁶g

Based on the law of mass conservation,

Mass of aldehyde coming in = mass of aldehyde going out = Rate of accumulation of aldehyde

Rate of accumulation of aldehyde in the steady state = 0

m*C*V= 0

m = 46 * 10⁻⁶g

C = concentration in the steady state

V = Volumetic flow of the fresh air

V = 600 ft³/min = 600 *60

V = 36000 ft³/hr

Density = Mass/volume

Density =  46 * 10⁻⁶g /36*10³

Density  = 1.28 * 10⁻⁹ g/ft³

If the density of air is taken as 36 g/ft³

concentration = (1.28 * 10⁻⁹ g/ft³)/36 g/ft³

concentration = 3.66 * 10⁻¹¹g/g

1*10⁻⁶g/g of air = 1ppm(part per million)

concentration of air =( 3.66 * 10⁻¹¹)(/1*10⁻⁶)

concentration of air = 3.66 * 10⁻⁵ppm = 0.0000366 ppm

concentration of air =  0.0000366 ppm is not sufficient to cause any eye irritation

7 0
3 years ago
What is the meaning of 52k?
amm1812

Answer:

52K is a form of money or amount. It basically means 52,000.

Explanation:

K stands for thousand.

4 0
3 years ago
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