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Diano4ka-milaya [45]
3 years ago
5

What are the three basic components of a limit switch​

Engineering
1 answer:
Tanzania [10]3 years ago
4 0

Answer:Body,Operator Head,Actuator

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What was a campaign belief in the 1980 presidential election? Carter called for a stronger national defense. Carter promised to
andreyandreev [35.5K]

Answer:

C

Explanation:

On edge 2021

6 0
3 years ago
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Neon is compressed from 100 kPa and 20◦C to 500 kPa in an isothermal compressor. Determine the change in the specific volume and
PIT_PIT [208]

Answer:

The specific volume is reduced in 80 per cent due to isothermal compression.

Specific enthalpy remains constant.

Explanation:

Let suppose that neon behaves ideally, the equation of state for ideal gases is:

P\cdot V = n\cdot R_{u}\cdot T

Where:

P - Pressure, measured in kilopascals.

V - Volume, measured in cubic meters.

n - Molar quantity, measured in kilomoles,

T - Temperature, measured in kelvins.

R_{u} - Ideal gas constant, measured in \frac{kPa\cdot m^{3}}{kmol\cdot K}.

On the other hand, the molar quantity (n) and specific volume (\nu), measured in cubic meter per kilogram, are defined as:

n = \frac{m}{M} and \nu = \frac{V}{m}

Where:

m - Mass of neon, measured in kilograms.

M - Molar mass of neon, measured in kilograms per kilomoles.

After replacing in the equation of state, the resulting expression is therefore simplified in term of specific volume:

P\cdot V = \frac{m}{M}\cdot R_{u}\cdot T

P\cdot \nu = \frac{R_{u}\cdot T}{M}

Since the neon is compressed isothermally, the following relation is constructed herein:

P_{1}\cdot \nu_{1} = P_{2}\cdot \nu_{2}

Where:

P_{1}, P_{2} - Initial and final pressure, measured in kilopascals.

\nu_{1}, \nu_{2} - Initial and final specific volume, measured in cubic meters per kilogram.

The change in specific volume is given by the following expression:

\frac{\nu_{2}}{\nu_{1}} = \frac{P_{1}}{P_{2}}

Given that P_{1} = 100\,kPa and P_{2} = 500\,kPa, the change in specific volume is:

\frac{\nu_{2}}{\nu_{1}} = \frac{100\,kPa}{500\,kPa}

\frac{\nu_{2}}{\nu_{1}} = \frac{1}{5}

The specific volume is reduced in 80 per cent due to isothermal compression.

Under the ideal gas supposition, specific enthalpy is only function of temperature, as neon experiments an isothermal process, temperature remains constant and, hence, there is no change in specific enthalpy.

Specific enthalpy remains constant.

8 0
3 years ago
Steam at 40 bar and 500o C enters the first-stage turbine with a volumetric flow rate of 90 m3 /min. Steam exits the turbine at
a_sh-v [17]

Answer:

(a) 62460 kg/hr

(b) 17,572.95 kW

(c) 3,814.57 kW

Explanation:

Volumetric flow rate, G = 30 m³ / 1 min => 90 / 60 => 1.5

Calculate for h₁ , h₂ , h₃

h₁ is h at P = 40 bar, 500°C => 3445.84 KJ/Kg

Specific volume steam, ц = 0.086441 m³kg⁻¹

h₂ is h at P = 20 bar, 400°C => 3248.23 KJ/Kg

h₃ is h at P = 20 bar, 500°C => 3468.09 KJ/Kg

h₄ is hg at P = 0.6 bar from saturated water table => 2652.85 KJ/Kg

a)

Mass flow rate of the steam, m = G / ц

m = 1.5 / 0.086441

m = 17.35 kg/s

mass per hour is m = 62460 kg/hr

b)

Total Power produced by two stages

= m (h₁ - h₂) + m (h₃ - h₁)

= m [(3445.84 - 3248.23) + (3468.09 - 2652.85)]

= m [ 197.61 + 815.24 ]

= 17.35 [1012.85]

= 17,572.95 kW

c)

Rate of heat transfer to the steam through reheater

= m (h₃ - h₂)

= 17.35 x (3468.09 - 3248.23)

= 17.35 x 219.86

= 3,814.57 kW

8 0
3 years ago
The tolerance for a geometric can be easily identified by reading the _________.
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Answer:

C

Explanation:

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Explain why the following scenario fails to meet the definition of a project description.
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Answer:

The youth hockey training facility

Explanation:

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