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Answer:
The rate of work output = -396.17 kJ/s
Explanation:
Here we have the given parameters
Initial temperature, T₁ = 355°C = 628.15 K
Initial pressure, P₁ = 350 kPa
h₁ = 763.088 kJ/kg
s₁ = 4.287 kJ/(kg·K)
Assuming an isentropic system, from tables, we look for the saturation temperature of saturated air at 4.287 kJ/(kg·K) which is approximately
h₂ = 79.572 kJ/kg
The saturation temperature at the given
T₂ = 79°C
The rate of work output =
×
×(T₂ - T₁)
Where;
= The specific heat of air at constant pressure = 0.7177 kJ/(kg·K)
= The mass flow rate = 2.0 kg/s
Substituting the values, we have;
= 2.0 × 0.7177 × (79 - 355) = -396.17 kJ/s
= -396.17 kJ/s
Answer:
The number of germanium atoms per cubic centimeter for this germanium-silicon alloy is 3.16 x 10²¹ atoms/cm³.
Explanation:
Concentration of Ge () = 15%
Concentration of Si (C) = 85%
Density of Germanium (ρ) = 5.32 g/cm³
Density of Silicon (ρ) = 2.33 g/cm³
Atomic mass of Ge (A)= 72.64 g/mol
To calculate the number of Ge atoms per cubic centimeter for the alloy, we will use the formula:
No of Ge atoms/cm³=[Avogadro's Number*]/([
*A
/ρ
)+(C
*A
/ρ
)]
= (6.02x10²³ * 15%) / [(15% * 72.64/5.32)+(72.64*85%/2.33)]
= (9.03x10²²)/(2.048+26.499)
= (9.03x10²²)/(28.547)
No of Ge atoms/cm³ = 3.16 x 10²¹ atoms/cm³