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3 years ago

An electric field around two charged objects is shown.

Physics

1 answer:

mamaluj [8]3 years ago

3 0

Answer: D

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X: positive

Y: negative

Explanation:

It's either A or D and I chose A and got it wrong.

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Describe the shapes and designs that are most aerodynamic.

Bas_tet [7]

The teardrop could be an example as it was designed for that purpose, and most notably planes and such aero traveling vehicles

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2 years ago

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What are valence electrons?

SashulF [63]

Answer:

The correct answer is D. Electrons in an atom that can bond with other atoms.

Explanation:

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2 years ago

Which of the following best describes Earth's crust, according to the theory of plate tectonics?

FrozenT [24]

Answer:

the Earth's crust is broken into about 12 plates that float on hotter, softer rocks in the underlying mantle

Explanation:

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2 years ago

** ANSWER IS A** As you move from left to right across Period 3, which statement is true of the number of

Sedbober [7]

Answer:

A. The number of valence electrons increases by 1.

Explanation:

As you move across any period on the periodic table, the number of valence electrons increases by a value of 1.

The periodic table of elements contains an arrangement of element by their atomic numbers.
From left to right, number of valence electrons increases.
Down a group, the valence electrons are the same.
Across a period, the number of valence electrons increases.

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2 years ago

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A 350-km-long high-voltage transmission line 2.00 cm in diameter carries a steady current of 1,010 A. If the conductor is copper

Masja [62]

Answer:

t = 47 years

Explanation:

To find the number of years in which the electrons cross the complete transmission, you first calculate the drift velocity of the electrons in the transmission line, by using the following formula:

$v_d=\frac{I}{nAq}$ (1)

I: current = 1,010A

A: cross sectional area of the transmission line = π(d/2)^2

d: diameter of the transmission line = 2.00cm = 0.02 m

n: free charge density = 8.50*10^28 electrons/m^3

q: electron's charge = 1.6*10^-19 C

You replace the values of all parameters in the equation (1):

$v_d=\frac{1010A}{(8.50*10^{28}m^{-3})(\pi(0.02m/2)^2)(1.6*10^{-19}C)}\\\\v_d=2.36*10^{-4}\frac{m}{s}$

with this value of the drift velocity you can calculate the time that electrons take in crossing the complete transmission line:

$t=\frac{d}{v_d}=\frac{350km}{2.36*10^{-4}m/s}=\frac{350000m}{2.36*10^{-4}m/s}\\\\t=1,483,050,847\ s$

Finally, you convert this value of the time to years:

$t=1,483,050,847s*\frac{1\ year}{3.154*10^7s}=47\ years$

hence, the electrons take around 47 years to cross the complete transmission line.

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2 years ago