Answer:
hjvakgVLLKFFFFSDHSSSSSSSSSSSSSSSSSSSSSSSSSS
initial velocity=0m/s
acceleration=4.2m/s^2
time taken =5s
then final velocity
v=u+at
or, v=0+4.2*5
so final velocity is 21m/s
Answer:
Explanation:The rate of decrease of velocity is given with respect to displacement. As v approaches zero when s approaches 39, it can be written as
where c=19
when s=8 we have
hence a can be found by the chain rule
From the equation
the s in term of t can be found
Hence it can be seen that if s approaches 39 the t function becomes undefined hence s is never 39m
Answer:
Yes my name is Robert I can help you
Answer:
62.5m
Explanation:
Given parameters:
Mass of the ball = 0.5kg
Initial velocity = 35m/s
At the maximum height final velocity is 0m/s
Unknown:
Height of the rise of the ball = ?
Solution:
To solve this problem, we apply the right motion equation which is shown below;
v² = u² - 2gh
v is the final velocity
u is the initial velocity
g is the acceleration due to gravity
h is the height
Now insert the parameters and solve;
0² = 35² - 2(9.8)(h)
-1225 = -19.6h
h = 62.5m