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amid [387]
3 years ago
13

Tom has a mass of 67.1 kg and Sally has a mass of 58.6 kg. Tom and Sally are standing 32.3 m apart on a massless dance floor. Sa

lly looks up and she sees Tom. She feels an attraction. If the attraction is gravitation, find its magnitude. Assume both can be replaced by point masses and that the gravitational constant is 6.67259 × 10−11 N · m2 /kg2 . Answer in units of N.
Physics
1 answer:
Gnom [1K]3 years ago
3 0

Answer:F=25.14\times 10^{-11} N

Explanation:

Given

mass of Tom(m_t)=67.1 kg

mass of sally(m_s)=58.6 kg

Distance between them(d)=32.3 m

Gravitational constant(G)=6.67\times 10^{-11} N.m^2/kg^2

Gravitational attraction is given by

F=\frac{Gm_1m_2}{d^2}

F=\frac{6.67\times 10^{-11}\times 67.1\times 58.6}{32.3^2}

F=25.14\times 10^{-11} N

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A 1050 W carbon-dioxide laser emits light with a wavelength of 10μm into a 3.0-mm-diameter laser beam. What force does the laser
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The force exerted by the laser beam on a completely absorbing target is 3.5 \times 10^{-6} \ N.

The given parameters;

  • <em>power of the laser light, P = 1050 W</em>
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The speed of the emitted laser light is given as;

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The force exerted by the laser beam on a completely absorbing target is calculated as follows;

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Learn more here:brainly.com/question/17328266

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