2 years ago

1.at constant temperature a gas occupy 50cm³ at 10mmhg calculate the work done

Physics

1 answer:

12345 [234]2 years ago

3 0

Answer:

100= 4 (n+7) simplify with steps :)

Explanation:

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What is the magnitude of the net torque on the pulley about the axle?

jeyben [28]

Answer: Torque= tangential force × radius of the pulley

Explanation:

Pulley is a simple machine which helps us to lift loads by applying the force in a convenient direction. It consists of a grooved wheel which is free to rotate about an axle passing through the center of the pulley.

For a pulley, the torque $T=$ tangential force × radius of the pulley

Pulleys can be used in combination also to achieve a desired output.

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3 years ago

A mountain-climber friend with a mass of 74 kg ponders the idea of attaching a helium-filled balloon to himself to effectively r

bazaltina [42]

Answer:

$V=16.65 m^3$

Explanation:

The volume of the balloon can be find compared the force in each cases so:

reduce 25% from 74kg

$R=\frac{25}{100}*74kg=18.5kg$

So the net force uproad on the balloon is

$F_b=18.5kg*g$

Now the density of the both gases air and helium are different however the volume is the same change offcorss the mass so:

$P_h=\frac{m}{V}=0.179 kg/m^3$

$P_A=1.29 kg/m^3$

$F_b=F_A-F_H$

$F_b=m_a*g-m_h*g$

$m=P/V$

$18.5kg*g=(1.29kg/m^3-0.179kg/m^3*)V*g$

$V=\frac{18.5kg}{(1.29-0.179)kg/m^3}$

$V=16.65 m^3$

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2 years ago

PLS HELP I HAVE EXAM ILL GIVE U BRAINLIST

stiv31 [10]

Explanation:

False

electron and proton attract each other

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3 years ago

List five situations in which a lesser amount of friction would be beneficial. Overall, would a high or low coefficient of frict

Natalka [10]

Low coefficient of friction

1. flying a plane (friction between air and plane)
2. ice skating (friction between ice and skate blade)
3. swimming (water & skin)
4. rowing a boat (water and boat)

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3 years ago

Read 2 more answers

Please don’t troll. I need someone to actually answer these questions.

mash [69]

Answer:

-3+3 i think this is the answer

Explanation:

i think you can ask someone else sorry

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2 years ago