Answer:
1.06 secs
Explanation:
Initial speed of sled, u = 8.4 m/s
Final speed of sled, v = 5.8 m/s
Coefficient of kinetic friction, μ = 0.25
Using the impulse momentum theory, we know that the impulse applied to the sled is equal to change in momentum of the sled:
FΔt = mv - mu
where m = mass of the object
Δt = time interval
F = force applied
The force applied on the sled is the frictional force, which is given as:
F = -μmg
where g = acceleration due to gravity
Therefore:
-μmgΔt = mv - mu
-μmgΔt = m(v - u)
-μgΔt = v - u
Making Δt subject of formula:
Δt = (v - u) / -μg
Δt = (5.8 - 8.4) / (-0.25 * 9.8)
Δt = -2.6/ -2.45
Δt = 1.06 secs
It took the sled 1.06 secs to travel from A to B.
Answer:
The answer to the question is
The magnitude of the displacement needed to get the ball into the hole in just one putt is 1.746m in the direction of 23.41° north east
Explanation:
With trigonometric relation and the attached diagram we have
From the diagram the location of the hole is 3.32m- (1.57 cos45 +0.78co45)m North and
1.57sin 45 – 0.78 sin 45 meters west
1.658m north and
0.55m east
Thus the direction of the hole is 26.41 degrees
North east
The magbitude of the displacement is displacement is gotten from the relation diplacement of x and y =√(x²+y²)
∠26.41°
<u>Answer:</u>
The acceleration of the car is 
<u>Explanation:</u>
In the question it is given that car initially heads north with a velocity 
. It then accelerates for 
and in the end its velocity is 
.
initial velocity 
time 
final velocity 
The equation of acceleration is
The value of acceleration is positive, here since the car is speeding up. If it was slowing down the value of acceleration would be negative.
Gravitational potential energy can be described as m*g*h (mass times gravity times height).
Originally,
15kg * 9.8m/s^2 *0.3 m = 44.1 kg*m^2/s^2 = 44.1 Joules.
After it is moved to a 1m shelf:
15kg * 9.8m/s * 1 = 147 kg*m^2/s^2= 147 Joules.
To find how much energy was added, we subtract final energy from initial energy:
147 J - 44.1 J = 102.9 Joules.
If the heat change of the surroundings (such as the solution the reaction is occurring in) is determined to be 2.7 kJ, what is the heat change of the reaction (qrxn)?
Answer: First of all we can conclude that this is an exothermic reaction. The reason being that an exothermic reaction is one that produces a temperature increase in a isolated system giving off heat to the surroundings. Therefore the heat of the reaction is a negative quantity (qrxn < 0).
I hope it helps, Regards.
