In nineteenth century, physical science was divided into discipline. .
2 answers:
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Answer:
Velocity of the passenger = 78.8[km/h]
Explanation:
In order to solve this problem, we must observe the train from a distant point of the train. In this way we can observe that the train moves at 80[km/h] relative to the ground.
In such a way that the passenger moves in a direction contrary to the movement of the train.
The Observer located outside the train will see how the passenger moves away at 78.8 [km / h] and not at 80[km/h] which is the speed of the train.
Answer:
(a) 80.36 m/s^2
(b) 0.0933 second
Explanation:
initial velocity, u = 7.5 m/s
final velocity, v = 0 m/s
distance moved, s = 0.350 m
(a) Let a be the deceleration.
Use third equation of motion
a = 80.36 m/s^2
Thus, the deceleration is 80.36 m/s^2.
(b) Let the time taken is t
Use first equation of motion
v = u + a t
0 = 7.5 + 80.36 x t
t = 0.0933 second
Answer:
For electric field inside cylinder, check image 02 attached
For electric field outside cylinder, check image 03 attached
Explanation:
Let's consider the polarized cylinder as superposition of two cylinders with opposite,equal, uniform charge densities in a way shown in the figure in the "image 01"d attached ;
In general, if we have an object with polarization (P¬) , then we have to take two objects with similar shape to the system, with opposite, equal, and uniform charge densities and then we super-impose these two objects in such a way that the total dipole moment of this superimposed system is equal to the total dipole moment of original system.
Now, we can take the super- imposed system as equivalent to the original system for calculating electric field and potential.
Therefore,
For the electric field inside the cylinder, check the solution in "image 02" i attached
For the electric field outside the cylinder, check, "image 03" i attached.
