Question #1:
a). The sketch is attached to this answer.
b). The equivalent resistance of 30Ω and 50Ω in parallel is
1 / (1/30 + 1/50) =
18.75 Ωc). I = V/R = (100/30) =
(3 and 1/3) Amperesd). Follow the wires, and you see that the 50Ω resistor is
connected directly to the battery, and so is the voltmeter.
So the voltage across the 50Ω resistor, and the reading
on the voltmeter, is
100 volts.e). I = V/R
Through the 30Ω resistor: I = 3-1/3 A
Through the 50Ω resistor: I = 2 A
f). In the parallel circuit, both resistors are connected
directly to the battery. So neither resistor even knows
that the other one is there.
Each resistor sees 100 volts,
and the current through each resistor is 100/R, just as if
it were the only resistor in the circuit.
For the given question above, I think there is an associated choice of answer for it. However, the answer for this is London Dispersion Forces. <span>Dipole-dipole forces and hydrogen bonding are much stronger, leading to higher melting and boiling points.</span>
Answer:
C. My soup will cool down because of radiation.
Explanation:
Since, there is vacuum between hot soup and its outside wall, then heat can not flow through conduction and convection.
The heat then only flows through radiation.
Therefore, the soup will not cool down because of convection or conduction by because of radiation.