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allsm [11]
3 years ago
5

I have a special thermos that has a vacuum chamber between my hot soup and its outside wall. Because my soup is isolated from it

s surrounding by a vacuum,
A. My soup will stay warm forever because thermal energy cannot pass through a vacuum.
B. My soup will cool down because of conduction.
C. My soup will cool down because of radiation.
D. My soup will cool down because of convection.E. Both B and D.
Physics
1 answer:
bagirrra123 [75]3 years ago
7 0

Answer:

C. My soup will cool down because of radiation.

Explanation:

Since, there is vacuum between hot soup and its outside wall, then heat can not flow through conduction and convection.

The heat then only flows through radiation.

Therefore, the soup will not cool down because of convection or conduction by because of radiation.

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A railroad car of mass M moving at a speed v1 collides and couples with two coupled railroad cars, each of the same mass M and m
marshall27 [118]

Answer:

vf = v₁/3 + 2v₂/3

Explanation:

Using the law of conservation of linear momentum,

momentum before impact = momentum after impact

So, Mv₁ + 2Mv₂ = 3Mv (since the railroad cars combine) where v₁ = initial velocity of first railroad car, v₂ = initial velocity of the other two coupled railroad cars, and vf = final velocity of the three railroad cars after impact.

Mv₁ + 2Mv₂ = 3Mvf

dividing through by 3M, we have

v₁/3 + 2v₂/3 = vf

vf = v₁/3 + 2v₂/3

6 0
3 years ago
A car starts from rest and accelerates uniformly over a time of 5.37 seconds for a distance of 101 m. Determine the acceleration
castortr0y [4]

Answer:

8.10m s-2

Explanation:

8 0
4 years ago
Which rope would have the longest wavelength-one with a frequency of 2 hz or one with a frequency of 3 hz?
Elis [28]
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\lambda =  \frac{v}{f}
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3 0
3 years ago
A grocery cart with a mass of 15 kg is pushed at constant speed along an aisle by a force fp = 12 n which acts at an angle of 17
Korolek [52]

<span>Given:

Mass of cart: 15kg</span>

Aisle length = 14m

Angle = 17° below the horizontal

Force fp = 12 N

 

So, the solution would be like this for this specific problem:

 

<span><span>1)    </span>W(by applied force) = F(applied) x s x cosθ <span>
=>W(a) = 12 x 14 x cos17* = 160.66 J </span></span>
<span><span>
2)    </span>By F(net) = F(applied) - F(friction) <span>
=>As v = constant => a = 0 => F(net) = 0 
=>F(applied) = F(friction) 
<span>=>W(friction) = -F(friction) x s
=>W(friction) = -F(applied) x s 
=>W(f) = -12 x 14 x cos17* = -160.56 J </span></span></span>
<span><span>
3)    </span>0, as the displacement is perpendicular to Force </span>
<span><span>
4)    </span>0, as the displacement is perpendicular to Force</span>  
<span>
To add, the force that is applied<span> to an object by a person or another object is called the applied force.</span></span>
8 0
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How much work does and elephant do pulling a circus wagon 1000m with<br> an applied force of 200 N?
RideAnS [48]

Answer:

2000000 J

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8 0
3 years ago
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