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3 years ago

Can anyone help me with any parts in question number 1: parallel circuit?

Physics

1 answer:

Leno4ka [110]3 years ago

4 0

Question #1:

a). The sketch is attached to this answer.

b). The equivalent resistance of 30Ω and 50Ω in parallel is

1 / (1/30 + 1/50) = 18.75 Ω

c). I = V/R = (100/30) = (3 and 1/3) Amperes

d). Follow the wires, and you see that the 50Ω resistor is
connected directly to the battery, and so is the voltmeter.
So the voltage across the 50Ω resistor, and the reading
on the voltmeter, is 100 volts.

e). I = V/R
Through the 30Ω resistor: I = 3-1/3 A
Through the 50Ω resistor: I = 2 A

f). In the parallel circuit, both resistors are connected
directly to the battery. So neither resistor even knows
that the other one is there. Each resistor sees 100 volts,
and the current through each resistor is 100/R, just as if
it were the only resistor in the circuit.

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A turntable reaches an angular speed of "45 rev/min" in "4.10 s" after being turned on. What is its angular acceleration?

Marina86 [1]

Answer:

1.15 rad/s²

Explanation:

given,

angular speed of turntable = 45 rpm

= $45\times \dfrac{2\pi}{60}$

= $4.71\ rad/s$

time, t = 4.10 s

initial angular speed = 0 rad/s

angular acceleration.

$\alpha = \dfrac{\omega_f-\omega_0}{t}$

$\alpha = \dfrac{4.71-0}{4.10}$

$\alpha = 1.15\ rad/s^2$

Hence, the angular acceleration of the turntable is 1.15 rad/s²

3 0

3 years ago

4. What's the voltage drop if V, = 56 V, V2 = 35 V, and V3 = 3 V

Murrr4er [49]

Answer:

The correct option is A. 18 V

Therefore,

$V_{1}=18\ V$

Explanation:

Given:

Total Voltage,

V = 56 V,

Voltage drop

$V_{2}=35\ V$

$V_{3}=3\ V$

To Find:

$V_{1}=?$ (Assumed ,as it is not given clearly in the question)

Solution:

So in series combination total Voltage is given as

$V=V_{1}+V_{2}+V_{3}$

Substituting the values we get

$56=V_{1}+35+3\\\\V_{1}=56-38=18\ V$

Therefore,

$V_{1}=18\ V$

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3 years ago

Write two differences between practical machine and ideal machine

slava [35]

Answer:

Ideal machines are said to have parts which are weightless , frictionless and strings if any are inextensible. Practical machines have parts which have weights, friction and it causes some loss of work done. So these are the differences between Ideal Machine and Practical Machines.

6 0

3 years ago

New York and Los Angeles are about 3000 mi apart, the time difference between these two cities is 3 h. Calculate the circumferen

aleksley [76]

Answer:

circumference of earth = 24000 miles

Explanation:

given data

New York and Los Angeles distance = 3000 mi

time difference = 3 h

to find out

circumference of the Earth

solution

we find speed first that is

speed = $\frac{distance }{time}$

speed = $\frac{3000}{3}$

speed = 1000 mph

now we know speed of earth is

speed = $\frac{circumference of earth}{time of rotation}$

circumference = speed × time of rotation

and we know earth take 24 hours to rotate at its axis

circumference of earth = 1000 × 24

circumference of earth = 24000 miles

7 0

4 years ago

A sailboat has a mass of 2160 kg and experiences two horizontal forces. One is due to the action of the water on the hull of the

NARA [144]

Answer:

Magnitude of the acceleration = 1.90 m/s²

Direction of the acceleration = 65.1° (measured counter clockwisely from the +x axis) or 65.1° north of East

Explanation:

The net force is the vector sum of all the forces acting on the sailboat.

One force is due to the action of the water on the hull of the boat and is directed east and has a magnitude of 1990 N; in vector form, F₁ = (1990j) N

The other force is due to the action of the wind on the sails and is directed northeast with a magnitude of 2440 N; in vector form, F₂ = 2440 [(cos 45°)î + (sin 45°)j] N = 1725î + 1725j) N

Net force = F₁ + F₂ = 1990j + (1725î + 1725j) = (1725î + 3715j) N

According to Newton's law, Net force causes acceleration of A body,

Net force = ma

a = (Net force)/m

a = (1725î + 3715j)/2160 = (0.80î + 1.72j) m/s²

Magnitude of acceleration

/a/ = √[(0.8²) + (1.72²)] = 1.90 m/s²

Direction of the acceleration = tan⁻¹ (1.72/0.8) = 65.1°

8 0

3 years ago