Your answer cannot be MORE precise than the least precise measurement. The following rule applies for multiplication and division: The LEAST number of significant figures in any number of the problem determines the number of significant figures in the answer.
(1.86 °c / 1 molal)×(2 molal) = 3.72°c, and because the temperature of the freezing point goes down the number has to be negative. So, the final answer is -3.72°c
Answer:
if chemistry hadn't been put up to practical use, we wouldn't truly understand the reason why humans are humans like makes up humans (including other understandings of biology, etc) and we wouldn't be able to have the advancements we have today (vaccines, etc).
Explanation:
Answer:
837.02 ohms
Explanation:
Step one:
Given data
Frequency= 60Hz
L1= 0.75H
L2= 1.47H
When inductors are connected in series, the total inductance is the sum of the individual inductance
Step two:
<u>Inductor 1</u>
<u>Inductor 2</u>
The total inductance is
=282.78+554.24
=837.02 ohms
Answer:
The weigth of a 90kg man standing on the moon is <u><em>147.6 N (option C)</em></u>
Explanation:
Weight is called the action exerted by the force of gravity on the body.
The mass (amount of matter that a body contains) of an object will always be the same, regardless of where it is located. Instead, the weight of the object will vary according to the force of gravity acting on it.
The formula that allows you to calculate the weight of any body is:
W = m*g
where:
- W = weight measured in N.
- m = mass measured in kg.
- g = acceleration of gravity measured in m/s². The acceleration of gravity g is the same for all objects that fall due to gravitational attraction, whatever their size or composition. For example, as an approximate value on Earth, g = 9.8 m/s².
In this case, the mass m has a value of 90 kg and the gravity g has a value of 1.64 m/s², which is the value of the acceleration of gravity of the moon. Then:
W=90 kg* 1.64 m/s²
<u><em>W= 147.6 N</em></u>
Finally, <u><em>the weigth of a 90kg man standing on the moon is 147.6 N (option C)</em></u>