Use t<span>he rule of 13 - the formula of a compound is a multiple </span>n<span> of 13 (the molar mass of </span>CH<span>) plus a remainder </span>r. <span>For </span>O<span>, add </span>O<span> and remove </span>CH₄ and f<span>or N, add N and remove one CH</span>₂<span>. 84 </span>÷ 13 = 6r6, the integer equals the number of carbon atoms and t<span>he integer </span>plus<span>the remainder equals the number of hydrogen atoms, </span>so possible formula is C₆H₁₂. M(C₆H₁₂) = 6 · 12,00 + 12 · 1,008 = 84,096. Add one oxygen atom to molecular formula: C₅H₈O. M(C₅H₈O) = 5 · 12,00 + 8 · 1,008 + 15,995 = 84,059, not. Add one nitrogen atom to molecular formula: C₅H₁₀N. M(C₅H₁₀N) = 5 · 12,00 + 10 · 1,008 + 14,003 = 84,083, not. If we add nitrogen and oxygen mass will be lower than 84,095, so molecular formula is C₆H₁₂.