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daser333 [38]
3 years ago
8

Write the molecular formula for a compound with the possible elements C, H, N and O that exhibits a molecular ion at M+ = 84.095

Chemistry
1 answer:
tia_tia [17]3 years ago
8 0
Use t<span>he rule of 13 - the formula of a compound is a multiple </span>n<span> of 13 (the molar mass of </span>CH<span>) plus a remainder </span>r. <span>For </span>O<span>, add </span>O<span> and remove </span>CH₄ and f<span>or N, add N and remove one CH</span>₂<span>.
84 </span>÷ 13 = 6r6, the integer equals the number of carbon atoms and t<span>he integer </span>plus<span> the remainder equals the number of hydrogen atoms, </span>so possible formula is C₆H₁₂.
M(C₆H₁₂) = 6 · 12,00 + 12 · 1,008 = 84,096.
Add one oxygen atom to molecular formula: C₅H₈O.
M(C₅H₈O) = 5 · 12,00 + 8 · 1,008 + 15,995 = 84,059, not.
Add one nitrogen atom to molecular formula: C₅H₁₀N.
M(C₅H₁₀N) = 5 · 12,00 + 10 · 1,008 + 14,003 = 84,083, not.
If we add nitrogen and oxygen mass will be lower than 84,095, so molecular formula is C₆H₁₂.

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