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enyata [817]
4 years ago
14

As a storm from moves in, you notice that a column of mercury in a barometer rises to 736 mm. (a) Determine the air pressure. (b

) If the mercury in the barometer is replaced with water, using the pressure you found in (a), to what height will the water level rise?
Chemistry
1 answer:
sesenic [268]4 years ago
5 0

Answer:

The air pressure is 9.8 *10^4 pa

The water will rise to a height of 10.0 meter

Explanation:

Step 1: Data given

As a storm from moves in, you notice that a column of mercury in a barometer rises to 736 mm.

Step 2: Calculate the air pressure

The Pressure against the mercury column = h*d*g = 0.736 * 13593 * 9.81 = 9.8 * 10^4 Pa

Step 3: Calculate the height of the water

Let the Pressure  the water column for same pressure is h meter : -

9.8 * 10^4 = h*d*g  

=>9.8*10^4 = h*1000*9.81  

=>h = 10.0 meter

The water will rise to a height of 10.0 meter

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Explanation:

The given data is as follows.

      Mass = 27.9 g/mol

As we know that according to Avogadro's number there are 6.023 \times 10^{26} atom present in 1 mole. Therefore, weight of 1 atom will be as follows.

            1 atoms weight = \frac{38}{6.023 \times 10^{26}}    

In a diamond cubic cell, the number of atoms are 8. So, n = 8 for diamond cubic cell.

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Now, we will calculate the volume of a lattice with lattice constant 'a' (cubic diamond) as follows.

                   = a^{3}

                   = (0.503 \times 10^{-9})^{3}

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Formula to calculate density of diamond cell is as follows.

               Density = \frac{mass}{volume}

                             = \frac{37.06 \times 10^{-26}}{0.127 \times 10^{-27} m^{3}}

                            = 2918.1 g/m^{3}

or,                         = 0.0029 g/cc       (as 1 m^{3} = 10^{6} cm^{3})

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3 years ago
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Answer:

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Explanation:

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<u>(Step 1)</u>

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