If I remember correctly from my science class, it is Protons and Neutrons.
Hope this helps, if not, comment below please!!!
Explanation:
The given data is as follows.
Mass = 27.9 g/mol
As we know that according to Avogadro's number there are
atom present in 1 mole. Therefore, weight of 1 atom will be as follows.
1 atoms weight =
In a diamond cubic cell, the number of atoms are 8. So, n = 8 for diamond cubic cell.
Therefore, total weight of atoms in a unit cell will be as follows.
= 
= 
Now, we will calculate the volume of a lattice with lattice constant 'a' (cubic diamond) as follows.
= 
= 
=
Formula to calculate density of diamond cell is as follows.
Density = 
= 
= 2918.1 
or, = 0.0029 g/cc (as 1
)
Thus, we can conclude that density of given semiconductor in grams/cc is 0.0029 g/cc.
Given molecule Lithium iodide (LiI)
Heat of hydration = -793 kj/mol
Lattice energy = -730 kJ/mol
Heat of hydration = Heat of solution - Lattice energy
Heat of solution = Hydration + Lattice = -793 + (- 730) = -1523 kJ/mol
Now,
Mass of LiI = 15.0 g
molar mass of LiI = 134 g/mol
# moles of LiI = 15/134 = 0.112 moles
Heat of solution for 1 mole of LiI = -1523 KJ
Therefore, for 0.112 moles of LiI the corresponding heat is
= 0.112 *(-1532) = 171.6 kJ
Answer:
volume = 0.288 L
Explanation:
To find the volume, you need to (1) convert grams LiBr to moles LiBr (via molar mass) and then (2) calculate volume (via molarity equation). It is important to arrange the ratios in a way tat allows for the cancellation of units (desired units in the numerator).
<u>(Step 1)</u>
Molar Mass (LiBr): 6.9410 g/mol + 79.904 g/mol
Molar Mass (LiBr): 86.845 g/mol
100 grams LiBr 1 mole
----------------------- x ------------------ = 1.15 moles LiBr
86.845 g
<u>(Step 2)</u>
Molarity (M) = moles / volume (L)
4 M = 1.15 moles / volume
(4 M) x volume = 1.15 moles
volume = 1.15 moles / 4 M
volume = 0.288 L