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2 years ago

An unknown liquid has a mass of 22.1 g

1 answer:

6 0

M = 22.1 g
V = 52.3 mL
D = ?

D = m/V
= 22.1/52.3
= 22.1*10/52.3*10
= 221/523
= 0.4

There. I’m sorry i forgot what exactly was the S.I. unit of density :(

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The amount of matter in a given amount of volume is referred to as

Damm [24]

Answer:

It would be Density because:

Density= mass/ volume

Density refers to the amount of matter or mass of a substance over a volume

7 0

2 years ago

How many Faradays of electricity are carried by 1.505×10^23 electronsk

aksik [14]

Mole of electron required by $1.505 *10^{23}$ mole is $2.5* 10 ^{-1}$

Faraday law expressed how the change that is been being produced by a current at an electrode-electrolyte interface is related and proportional to the quantity of electricity that is been used.

There is one mole of electron required for 1 Faraday of electricity.

Avogadro constant is $6.02*10^{23}$

Mole of electron can be calculated by dividing the number of electron by avogadro's constant.

= $\frac{1.505*10^{23} }{6.02*10^{23} }$

= $2.5* 10^{-1} Faraday of electricity$

Therefore, it requires $2.5*10^{-1}$ Faraday of electricity for the $1.505 * 10^{23} mole.$

Learn more at: brainly.com/question/1640558?referrer=searchResults

3 0

2 years ago

You are instructed to create 900. mL of a 0.29 M phosphate buffer with a pH of 7.8. You have phosphoric acid and the sodium salt

Aleksandr [31]

Answer:

B and C

Explanation:

When we have to do a buffer solution we always have to choose the reaction that has the pKa closer to the desired pH value. When we find the pKa values we will obtain:

$pKa_1=-Log[6.9x10^-^3]=2.16$

$pKa_2=-Log[6.2x10^-^8]=7.20$

$pKa_3=-Log[4.8x10^-^13]=12.31$

The closer value is pKa2 with a value of 7.2. Therefore we have to use the second reaction. In which $H_2PO_4^-^1$ is the acid and $HPO_4^-^2$ is the base. Therefore the answer for the first question is B and the answer for the second question is C.

8 0

2 years ago

By mistake, you added salt instead of sugar to the oil. How can you remove the salt?

Jet001 [13]

Answer:

by adding water into the mix

Explanation:

this will dissolve the salt

5 0

2 years ago

Read 2 more answers

What is the volume of 3.00 M sulfuric aid that contain 9.809 g of H2SO4 (98.09g/mol)

Slav-nsk [51]

Given :

Molarity of sulfuric acid solution is 3.0 M.

Amount of sulfuric acid present in solution is 9.809 g.

To Find :

The volume of solution.

Solution :

We know, molarity is given by :

$Molarity = \dfrac{number \ of \ moles \times 1000}{Volume\ ( ml )}\\\\M = \dfrac{w \times 1000}{M.M \times V}\\\\3 = \dfrac{9.809\times 1000}{98.09 \times V}\\\\V = \dfrac{1000}{10\times 3}\ ml\\\\V = 33.33 \ ml$

Therefore, volume required is 33.33 ml .

5 0

3 years ago