In a church choir loft, two parallel walls are 5.30 m apart. The singers stand against the north wall. The organist faces the so
1 answer:
The virtual image is as far behind the mirror as the choir is in front of the mirror. Thus, the image is 5.30 m behind the mirror. The image of the choir is 0.800 m+ 5.30 m= 6.10 m from the organist.
<u>Using</u><u> similar triangles</u><u>:</u>
h'/0.600 = 6.10/0.800
So, h' = 0.600( 6.10/0.800 ) = 4.58m
<h3><u>The concept of Ray Optics and Optical Instrument</u></h3>A subject of physics called Ray Optics and Optical Instruments investigates the characteristics and behavior of light. When light moves in a straight line, as in ray optics, also known as geometrical optics, it is said that every object has an image. The optical tools that are now in use make use of the reflecting and refracting qualities of mirrors, lenses, and prisms.
<h3><u>What is ray optics ?</u></h3>The theory of ray optics, often known as geometrical optics, describes how light travels in terms of rays. It discusses how light behaves. Typically, light is thought of as a beam that follows a straight path.
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Answer:
a. 79.1 N
b. 344 J
c. 344 J
d. 0 J
e. 0 J
Explanation:
a. Since the crate has a constant velocity, its net force must be 0 according to Newton's 1st law. The push force by the worker must be equal to the friction force
on the crate, which is the product of friction coefficient μ and normal force N:
Let g = 9.81 m/s2
b. The work is done on the crate by this force is the product of its force and the distance traveled s = 4.35
c. The work is done on the crate by friction force is also the product of friction force and the distance traveled s = 4.35
This work is negative because the friction vector is in the opposite direction with the distance vector
d. As both the normal force and gravity are perpendicular to the distance vector, the work done by those forces is 0. In other words, these forces do not make any work.
e. The total work done on the crate would be sum of the work done by the pushing force and the work done by friction
Answer:
The answer of the part (a) is v2 = 7.09 m/s
and the answer of the part (b) is vA1 = 5.25 m/s
Explanation:
Explanation of the both parts of answer is in the following attachments
