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emmainna [20.7K]
4 years ago
14

What potential difference is required to cause 4.00 a to flow through a resistance of 330 ω?

Physics
1 answer:
Alisiya [41]4 years ago
7 0
We can solve the problem by using Ohm's law, which states that an Ohmic conductor the following relationship holds:
\Delta V = I R
where
\Delta V is the potential difference applied to the resistor
I is the current flowing through it
R is the resistance

In our problem, I=4.00 A and R=330 \omega, so the potential difference is
\Delta V = IR=(4.00 A)(330 \omega)=1320 V
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Answer:

0.08 N/C

Explanation:

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E = Kq/r².............................. Equation 1

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making q the subject of the equation,

q = Er²/k............................... Equation 2

Given: E = 2 N/C, r = 4 m,

Substitute into equation 2

q = 2(4)²/k

q = 32/k C.

When r is increased to 20 m,

E = k(32/k)/20²

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5 0
4 years ago
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Vika [28.1K]

Answer:

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Explanation:

Data given:

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To Find:

Height of the building = ?

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                                      2aS= Vf² - Vi²                      ( S= h , a=g)

                                     2*9.81*h = (30)² - (0)²

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3 years ago
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Different forms of energy exists such as heat, thermal, chemical, mechanical, sound, electrical, e.t.c

Learn more:

Energy brainly.com/question/8727665

#learnwithBrainly

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if object a and object b collide object a have the same momentum as it had before the collision. T or F
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The correct answer is: *False <------
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