Question

What potential difference is required to cause 4.00 a to flow through a resistance of 330 ω?

Answer 1

We can solve the problem by using Ohm's law, which states that an Ohmic conductor the following relationship holds:
$\Delta V = I R$
where
$\Delta V$ is the potential difference applied to the resistor
I is the current flowing through it
R is the resistance

In our problem, I=4.00 A and $R=330 \omega$, so the potential difference is
$\Delta V = IR=(4.00 A)(330 \omega)=1320 V$