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emmainna [20.7K]
3 years ago
14

What potential difference is required to cause 4.00 a to flow through a resistance of 330 ω?

Physics
1 answer:
Alisiya [41]3 years ago
7 0
We can solve the problem by using Ohm's law, which states that an Ohmic conductor the following relationship holds:
\Delta V = I R
where
\Delta V is the potential difference applied to the resistor
I is the current flowing through it
R is the resistance

In our problem, I=4.00 A and R=330 \omega, so the potential difference is
\Delta V = IR=(4.00 A)(330 \omega)=1320 V
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5 0
2 years ago
Read 2 more answers
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PilotLPTM [1.2K]

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Explanation:

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3 0
2 years ago
The number of bacteria in a certain population increases according to a continuous exponential growth model, with a growth rate
sveta [45]

Answer:

It would take approximately 289 hours for the population to double

Explanation:

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N(t)=N_0\,e^{kt}

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In our case, we don't know No (original population, but know that we want it to double in a certain elapsed "t". We also have in mind that the percent rate "k" would be expressed in mathematical form as: 0.0024 (mathematical form of the given percent growth rate).

So we need to solve for "t" in the following equation:

2\,N_0=N_0\,e^{0.0024\,t}\\\frac{2\,N_0}{N_0} =e^{0.0024\,t}\\2=e^{0.0024\,t}\\ln(2)=0.0024\,t\\t=\frac{ln(2)}{0.0024} \\t=288.811\,\, hours

Which can be rounded to about 289 hours

6 0
3 years ago
A metallic wire has a diameter of 4.12mm. when the current in the wire is 8.00a, the drift velocity is 5.40×10−5m/s.
Darina [25.2K]
R = 2.06 mm = 2.06 x 10^(-3) m
Q = 1.6 x 10^(-19) C
v = 2.5 x 10^(-5) m/s
I = 8 A = 8 C/s
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= 1.3325 x 10^(-5) m²
I = n Q v A
n = I / (Q v A)
n = 8 C/s / ( 1.6 x 10 ^(-19) * 5.4 x 10^(-5) * 1.3325 x 10^(-5) ) = 
= 0.694 x 10^(29) m^(-3)
n = 6.94  x 10^(28)   m^(-3)
8 0
3 years ago
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