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expeople1 [14]
2 years ago
8

A car is travelling along a straight road with speed v measured in m/s. The power P measured in watts required to overcome exter

nal forces opposing the motion is given by the p=CV+KV³, where c and k are constants. use base units to obtain SI unit for constant K​
Physics
1 answer:
mojhsa [17]2 years ago
5 0

Answer:

K = kg/m

Explanation:

as velocity has units of m/s  V³ has units of m³/s³

power has units of J/s = N•m/s = kg•m/s²•m/s = kg•m²/s³

kg•m²/s³ = K(m³/s³)

K = kg•m²/s³•s³/m³

K = kg/m

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why is the earth more attracted to the sun gravitational pull than the gravitational pull of the moon
Ierofanga [76]
First, let's take a look at the equation for the force of gravity between two objects:

F = (GMm)/r², where, 

G = gravitational constant = 6.67 x 10⁻¹¹
M = mass of one object
m = mass of the other object
r = distance between the two objects

From this equation, we can see that the force of gravity is directly proportional to the mass of the two objects and inversely proportional to the distance between them. We can then say that the Earth is <span>more attracted to the sun than the moon because of the massive mass of the Sun (1.9891 x 10</span>³⁰)<span> compared to moon (7.3577 x 10</span>²²<span>). Although, the moon is nearer to the Earth, it has little effect to bring down the gravitational pull of the Sun. </span>
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3 years ago
a man of mass 50 kg on the top floor of skyscraper step into an elevator what is the max weight as the elevator moves downward​
shtirl [24]
514.5 N is the answer
6 0
2 years ago
When light is reflected, the incident rays are bent and change direction.<br> True<br> False
Helga [31]

Answer: True

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8 0
3 years ago
Read 2 more answers
You are standing on a large sheet of frictionless ice and holding a large rock. In order to get off the ice, you throw the rock
kondor19780726 [428]

Answer:

0.4778 m/s

Explanation:

To solve this question, we will make use of law of conservation of momentum.

We are given that the rock's velocity is 12 m/s at 35°. Thus, the horizontal component of this velocity is;

V_x = (12 m/s)(cos(35°)) = 9.83 m/s.

Thus, the horizontal component of the rock's momentum is;

(3.5 kg)(9.83 m/s) = 34.405 kg·m/s.

Since the person is not pushed up off the ice or down into it, his momentum will have no vertical component and so his momentum will have the same magnitude as the horizontal component of the rock's momentum.

Thus, to get the person's speed, we know that; momentum = mass x velocity

Mass of person = 72 kg and we have momentum as 34.405 kg·m/s

Thus;

34.405 = 72 x velocity

Velocity = 34.405/72

Velocity = 0.4778 m/s

6 0
3 years ago
Inside a NASA test vehicle, a 3.50-kg ball is pulled along by a horizontal ideal spring fixed to a friction-free table. The forc
erastova [34]
F(of spring)=230x=ma=3.5(5)=17.5=230x; x=0.07m.
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2 years ago
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