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Vaselesa [24]
2 years ago
15

A ball is launched from a 300m cliff and lands 380m away from the cliff in 9 seconds. Calculate the initual speed and the angle

of the ball when it was launched.​
Physics
1 answer:
Marysya12 [62]2 years ago
6 0

Answer:

Explanation:

Given

Maximum height H = 300m

Range (horizontal distance) = 380m

Required

Initial speed U and the angle of the ball when it was launched.​

Range = U√2H/g

380 = U√2(300)/9.8

380 = U√600/9.8

380 = 7.8246U

U = 380/7.8246

U = 48.57m/s

The initial speed is 48.57m/s

b) Using the formula for calculating time of flight;

T = 2Usin theta/g

9 = 2(48.57)sin theta/9.8

9*9.8 = 97.14sin theta

88.2 = 97.14sin theta

88.2/97.14 = sin theta

sin theta = 0.9079

theta = sin^-1(0.9079)

theta = 65.23°

hence the angle when the ball was launched is 65.23°

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The time taken by the light reflected from sun to reach on earth will be 8.4 minutes.

To find the answer, we need to know about the distance travelled by light.

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         d=(1.5*10^8km)+2(3.8*10^5km)=1.51*10^8km=1.51*10^{11}m

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                      t=\frac{1.51*10^{11}}{3*10^8}=503.33 s\\t=\frac{503.33}{60}=8.4min

Thus, the time it takes for the light from the Sun to reach Earth and be recognized as 8.4 minutes.

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Older televisions display a picture using a device called a cathode ray tube, where electrons are emitted at high speed and coll
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Answer:

Explanation:

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horizontal distance covered = 5.5 x 10⁻² m

time taken to cover horizontal distance =  5.5 x 10⁻² / 2.1  x 10⁷

= 2.62 x 10⁻⁹ s .

b )

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= .5 x 5.1 x 10¹⁵ x (2.62 x 10⁻⁹)²

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power of a crane is 25000 watt calculate the time required by it to lift a load of 6000 kg up tp the height of 20 m​
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Solution:

We have,

Power [P] = 25000 Watt

Mass [m] = 6000 kg

Height [h] = 20 metres

Time [t] = ?

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Or, t = 6000 x 10 x 20/25000

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Therefore, t = 48 second

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