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Marat540 [252]
3 years ago
14

A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 4.0 m/s. The car is a distanc

e away. The bear is 26m behind the tourist and running at 6.0 m/s. The tourist reaches the car safely. What is the maximum possible values for d?
Physics
1 answer:
Brums [2.3K]3 years ago
4 0

For this specific problem, the maximum value for d is 52m. I am hoping that this answer has satisfied your query about and it will be able to help you, and if you’d like, feel free to ask another question.

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Imagine you have a collection of identical flat-bottomed coffee filters that can be nested (stacked inside of each other) so tha
skad [1K]

Answer:

the terminal velocity of 14 nested coffee filters is 3.2 m/s

Explanation:

Given the data in the question;

we know that;

The terminal velocity is proportional to the square root of weight.

v ∝ √W

v = k√W

the proportionality constant depends upon the surface area and the density of the medium (like air). The coffee filters can be stacked such that the resulting area is roughly unchanged. So, the constant of proportionality k is also unchanged

v/√W = constant

v₂/√W₂ = v₁/√W₁

v₂ = v₁√(W₂ / W₁ )

given that;

v₁ = 0.856 m/s,

W₂ = 14W₁; meaning 14 coffee filters have 14 times the weight of a single coffee filter

so we substitute

v₂ = 0.856 √(14W₁  / W₁ )

v₂  = 0.856 √( 14( W₁/W₁)

v₂  = 0.856 √( 14(1)

v₂  = 0.856 √( 14 )

v₂  = 0.856 × 3.741657

v₂  = 3.2 m/s

Therefore, the terminal velocity of 14 nested coffee filters is 3.2 m/s

6 0
3 years ago
The bodies of many cars are designed to compress or crumple during an accident. Why are cars built with a crumple zone?
Kryger [21]
By collapsing and crumpling, the force and energy is absorbed by the crumple zone and it is not transferred to the passengers inside. This is a safety feature for the passengers.
8 0
3 years ago
How density of substance change with change in temperature?
Anna71 [15]

The answer is above but I don't know if it's correct.

7 0
2 years ago
A man is standing on the edge of a 20.0 m high cliff. He throws a rock horizontally with an initial velocity of 10.0 m/s. How lo
Arlecino [84]

Answer:

t = 4.08 s

R = 40.8 m

Explanation:

The question is asking us to solve for the time of flight and the range of the rock.

Let's start by finding the total time it takes for the rock to land on the ground. We can use this constant acceleration kinematic equation to solve for the displacement in the y-direction:

  • Δx = v_0 t + 1/2at²

We have these known variables:

  • (v_0)_y = 0 m/s
  • a_y = -9.8 m/s²
  • Δx_y = -20 m

And we are trying to solve for t (time). Therefore, we can plug these values into the equation and solve for t.

  • -20 = 0t + 1/2(-9.8)t²
  • -20 = 1/2(-9.8)t²
  • -20 = -4.9t²
  • t = 4.08 sec

The time it takes for the rock to reach the ground is 4.08 seconds.

Now we can use this time in order to solve for the displacement in the x-direction. We will be using the same equation, but this time it will be in terms of the x-direction.

List out known variables:

  • v_0 = 10 m/s
  • t = 4.08 s
  • a_x = 0 m/s

We are trying to solve for:

  • Δx_x = ?

By using the same equation, we can plug these known values into it and solve for Δx.

  • Δx = 10 * 4.08 + 1/2(0)(4.08)²
  • Δx = 10 * 4.08
  • Δx = 40.8 m

The rock lands 40.8 m from the base of the cliff.

7 0
3 years ago
Debris from the solar system strikes the Earth as which of the following​
gogolik [260]

Answer: Meteors

Explanation:

7 0
3 years ago
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