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chubhunter [2.5K]
2 years ago
8

What is the volume of a balloon if it contains 3.2 moles of helium at a temperature of 20. °C and standard pressure?

Chemistry
1 answer:
KatRina [158]2 years ago
3 0

Answer:

1.14 mol

Explanation:

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Write the electron configuration for a sodium cation with a charge of 1+
Dafna1 [17]

1{s}^{2} 2 {s}^{2} 2 {p}^{6}

or simply 2,8 it is isoelectronic with argon

4 0
3 years ago
What is the luster of aluminum
Mamont248 [21]

Answer:

Luster of aluminum is Silver-White.

Explanation:

Aluminium is a Silver-White metal which is extracted from the Bauxite ore which can be reddish brown, white, tan, grey-white and tan-yellow in color and have the minerals like Gibbsite, Boehmite and Diaspore which are the minerals of the aluminium.

The Bauxite is the rock from which the Bauxite ore is extracted which have the minerals of the aluminum.

The luster of a metal is the color and shine of it and its shiny appearance.

Aluminium is a light weight metal but have a moderate hardness which makes a wider use of it. Aluminium is used in many places where the weight of the material is kept light but its hardness can be increased by mixing some other metals in it making hard alloy with lighter weight.

It is used in transportation vehicles, buildings, and many other places like Air crafts as the weight should be kept controlled to give a perfect lift to the Air craft.

3 0
3 years ago
12a. How does the model of the volcano provide evidence for the cycling of Earth materials through the rock cycle?
Bond [772]

Answer:

lava is coming from the crust

Explanation:

volcano's explode with lava because the crust pushes it out

6 0
2 years ago
A gas has a volume of 1.75L at -23°C and 150.0 kPa. At what temperature would the gas occupy 1.30L at 210.0 kPa?
Nastasia [14]

Answer:

At -13 ^{0}\textrm{C} , the gas would occupy 1.30L at 210.0 kPa.

Explanation:

Let's assume the gas behaves ideally.

As amount of gas remains constant in both state therefore in accordance with combined gas law for an ideal gas-

                                          \frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}

where P_{1} and P_{2} are initial and final pressure respectively.

           V_{1}  and V_{2} are initial and final volume respectively.

           T_{1} and T_{2} are initial and final temperature in kelvin scale respectively.

Here P_{1}=150.0kPa , V_{1}=1.75L , T_{1}=(273-23)K=250K, P_{2}=210.0kPa and V_{2}=1.30L

Hence    T_{2}=\frac{P_{2}V_{2}T_{1}}{P_{1}V_{1}}

            \Rightarrow T_{2}=\frac{(210.0kPa)\times (1.30L)\times (250K)}{(150.0kPa)\times (1.75L)}

            \Rightarrow T_{2}=260K

            \Rightarrow T_{2}=(260-273)^{0}\textrm{C}=-13^{0}\textrm{C}

So at -13 ^{0}\textrm{C} , the gas would occupy 1.30L at 210.0 kPa.

5 0
3 years ago
What is the net ionic equation for the reaction of alum (KAl(SO4)2.12H2O.) and KOH?
Lesechka [4]
<span>The net ionic equation for the reaction of alum (KAl(SO4)2.12H2O.) and KOH is </span>the solid AlOH3  formed.
7 0
3 years ago
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