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lutik1710 [3]
3 years ago
14

What would a substance that could undergo condensation polymerization most likely have? two double bonds a triple bond two aldeh

yde functional groups two alcohol functional groups
Chemistry
2 answers:
Rina8888 [55]3 years ago
7 0

Answer:

Two alcohol functional groups

Explanation:

Hello,

Condensation polymerizations are based on the releasing of water after the undergoing chemical reactions. In this manner, an illustrative example is shown below:

nHO-R-OH--->(O-R-)_n+2nH_2O

This is caused by high reactivity of the hydroxide ions when they are together allowing the polymerization to take place.

Best regards.

blagie [28]3 years ago
5 0
The fourth option on Edgen, "two alcohol functional groups". You're welcome :)
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Illusion [34]

Answer:

V = 2.75 L

Explanation:

Given that,

Mass of liquid glycerol, m = 3470 g

The density of liquid glycerol, d = 1.26 g/cm³

We need to find the volume of liquid glycerol.

We know that,

Density=mass/volume

V=\dfrac{m}{d}\\\\V=\dfrac{3470\ g}{1.26\ g/cm^3}\\\\V=2753.96\ cm^3

We know that, 1 cm³ = 0.001 L

V = 2.75 L

So, the volume of liquid glycerol is 2.75 L.

6 0
4 years ago
TRUE OR FALSE
Neko [114]

Answer:

False.

Explanation:

Friction is a resisting force that acts on a body to prevent its motion. Friction force acts opposite to the direction of motion.

7 0
3 years ago
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Diamonds are measured in carats, and 1 carat=0.200g. The density of diamond is 3.51g/cm^3. What is the volume of a 5.0-carat dia
const2013 [10]
Convert the amount of substance in carat to grams.
                 (5.0 carat) x (0.200 g / 1 carat) = 1 g
The volume of the substance is obtained by dividing the mass by the density,
                             v = m / d
                             v = 1 g / (3.51 g/cm³) = 0.2849 cm³
Therefore, the volume of a 5.0 carat diamond is approximately 0.285 cm³.
7 0
4 years ago
What is the entropy of this collection of training examples with respect to the positive class B. What are the information gains
Alenkinab [10]

The data set is missing in the question. The data set is given in the attachment.

Solution :

a). In the table, there are four positive examples and give number of negative examples.

Therefore,

$P(+) = \frac{4}{9}$   and

$P(-) = \frac{5}{9}$

The entropy of the training examples is given by :

$ -\frac{4}{9}\log_2\left(\frac{4}{9}\right)-\frac{5}{9}\log_2\left(\frac{5}{9}\right)$

= 0.9911

b). For the attribute all the associating increments and the probability are :

  $a_1$   +   -

  T   3    1

  F    1    4

Th entropy for   $a_1$  is given by :

$\frac{4}{9}[ -\frac{3}{4}\log\left(\frac{3}{4}\right)-\frac{1}{4}\log\left(\frac{1}{4}\right)]+\frac{5}{9}[ -\frac{1}{5}\log\left(\frac{1}{5}\right)-\frac{4}{5}\log\left(\frac{4}{5}\right)]$

= 0.7616

Therefore, the information gain for $a_1$  is

  0.9911 - 0.7616 = 0.2294

Similarly for the attribute $a_2$  the associating counts and the probabilities are :

  $a_2$  +   -

  T   2    3

  F   2    2

Th entropy for   $a_2$ is given by :

$\frac{5}{9}[ -\frac{2}{5}\log\left(\frac{2}{5}\right)-\frac{3}{5}\log\left(\frac{3}{5}\right)]+\frac{4}{9}[ -\frac{2}{4}\log\left(\frac{2}{4}\right)-\frac{2}{4}\log\left(\frac{2}{4}\right)]$

= 0.9839

Therefore, the information gain for $a_2$ is

  0.9911 - 0.9839 = 0.0072

$a_3$     Class label      split point       entropy        Info gain

1.0         +                        2.0            0.8484        0.1427

3.0        -                         3.5            0.9885        0.0026

4.0        +                        4.5            0.9183         0.0728

5.0        -

5.0        -                        5.5            0.9839        0.0072

6.0        +                       6.5             0.9728       0.0183

7.0        +

7.0        -                        7.5             0.8889       0.1022

The best split for $a_3$  observed at split point which is equal to 2.

c). From the table mention in part (b) of the information gain, we can say that $a_1$ produces the best split.

4 0
3 years ago
Which cell organelle is where proteins are made? A. nucleus B. ribosome C. vacuole D. mitochondrion
N76 [4]

Answer:

B. ribosome

Explanation:

In the ribosomes, the codons get paired with anti codons to create a polypeptide or protein.

5 0
4 years ago
Read 2 more answers
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