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eduard
3 years ago
11

Determine the final temperature of sample with a specific heat of 1.1 J/g°C and a mass of 385 g if it starts out at a temperatur

e of 19.5°C and 885 J of energy are added to it.
Chemistry
1 answer:
Assoli18 [71]3 years ago
8 0

Answer:

T2 =21.52°C

Explanation:

Given data:

Specific heat capacity of sample = 1.1 J/g.°C

Mass of sample = 385 g

Initial temperature = 19.5°C

Heat absorbed = 885 J

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = Final temperature - initial temperature

885J = 385 g× 1.1 J/g.°C×(T2 - 19.5°C )

885 J = 423.5 J/°C× (T2 - 19.5°C )

885 J / 423.5 J/°C = (T2 - 19.5°C )

2.02°C = (T2 - 19.5°C )

T2 = 2.02°C + 19.5°C

T2 =21.52°C

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3 years ago
How many moles of gas occupy 98L at a pressure of 2.8atm and a temperature of 292k? and what law would you use?
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Let's assume that the gas has ideal gas behavior.

Then we can use ideal gas equation,
PV = nRT

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The given data for the gas is,
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