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VikaD [51]
1 year ago
9

Two cars A and B are moving in opposite directions with the velocity of 20m/s and 6m/s respectively Calculate the relative of ca

r A with respect to car B If they move in the same velocity what will be the relative velocity of CarA with respect to Car B​
Chemistry
1 answer:
olga nikolaevna [1]1 year ago
8 0

The relative velocity is described as the velocity of an object with respect to another viewer. It is the time rate of shift of relative position of one object with respect to another object.

<h3>How to  find out the Relative Velocity of car A and car B ?</h3>

a) Velocity of car A (Va) = 20m/s

Velocity of car B (Vb) = -6m/s

To find the Relative Velocity, we should apply the formula as,

Relative Velocity of car A and car B = Vab

Vab = Va - Vb

Vab = 20 - (-6)

Vab = 20+6

Vab = 26m/s

b). if Velocity of car A = Velocity of car B

Va = Vb

In this case,

Relative Velocity = Vab

Vab = Va - Vb

(since Va = Vb)

Vab = 0m/s

Hence, the Relative Velocity in a). is 26m/s and in b). is 0m/s.

To learn more about  relative velocity, refer

brainly.com/question/17228388

#SPJ9

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Lelechka [254]

5mg in liter is 5 ppm

Explanation: 1 ppm is one part per million.

1 ppm is 1 mg is one part of million from 1 kg = 1000 000 mg

1 litre water is 1. Kg.

3 0
2 years ago
A sample of gas in a 14.6 L flexible container is at 25.0oC and 1.00atm. What is the volume of the sample when heated to 220.0oC
inn [45]

Answer: 24.1 L

Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=14.6L\\T_1=25.0^oC=(25+273)K=298K\\V_2=?\\T_2=220.0^0C=(220+273)K=493K

Putting values in above equation, we get:

\frac{14.6}{298K}=\frac{V_2}{493}\\\\V_2=24.1L

Thus the volume of the sample when heated to 220.0oC and the pressure is constant is 24.1 L

7 0
3 years ago
calculate δg o for each reaction using δg o f values: (a) h2(g) i2(s) → 2hi(g) 2.6 kj (b) mno2(s) 2co(g) → mn(s) 2co2(g) kj (c)
Reika [66]

(a)The change in Gibbs free energy for the reaction has been 2.6 kJ/mol.

(b) The change in Gibbs free energy for the reaction has been -49.3 kJ/mol.

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Explanation:

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The photosynthesis chemical equation states that the reactants (carbon dioxide, water and sunlight), yield two products, glucose and oxygen gas. The single chemical equation represents the overall process of photosynthesis.

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Hope this helps!

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