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VikaD [51]
1 year ago
9

Two cars A and B are moving in opposite directions with the velocity of 20m/s and 6m/s respectively Calculate the relative of ca

r A with respect to car B If they move in the same velocity what will be the relative velocity of CarA with respect to Car B​
Chemistry
1 answer:
olga nikolaevna [1]1 year ago
8 0

The relative velocity is described as the velocity of an object with respect to another viewer. It is the time rate of shift of relative position of one object with respect to another object.

<h3>How to  find out the Relative Velocity of car A and car B ?</h3>

a) Velocity of car A (Va) = 20m/s

Velocity of car B (Vb) = -6m/s

To find the Relative Velocity, we should apply the formula as,

Relative Velocity of car A and car B = Vab

Vab = Va - Vb

Vab = 20 - (-6)

Vab = 20+6

Vab = 26m/s

b). if Velocity of car A = Velocity of car B

Va = Vb

In this case,

Relative Velocity = Vab

Vab = Va - Vb

(since Va = Vb)

Vab = 0m/s

Hence, the Relative Velocity in a). is 26m/s and in b). is 0m/s.

To learn more about  relative velocity, refer

brainly.com/question/17228388

#SPJ9

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When you have a free metal ion, how do the energies of these orbitals relate to one another (are they the same, different, etc.)
7nadin3 [17]

Answer:

The energy of the orbitals are the same

Explanation:

For a free metal ion, all the d-orbitals are of the same energy. The five d-orbitals are said to be five fold degenerate in the free metal ion. Hence all the d-orbitals will possess the same energy irrespective of which one is first filled.

In an octahedral or tetrahedral crystal field, the d-orbitals will loose their degeneracy and become different in energy based on their orientation towards the ligands.

4 0
3 years ago
When water vapor cools it condenses select the number that represents this process on the diagram
TiliK225 [7]
2 is the correct answer.
6 0
3 years ago
Read 2 more answers
. The ring shape of the Cartwheel Galaxy is due to:
dlinn [17]

The ring shape of the Cartwheel Galaxy is due to collisions with another galaxy.

<h3>What causes the ring shape of the Cartwheel Galaxy?</h3>

The unusual shape of the Cartwheel Galaxy is due to a collision with a smaller galaxy. The recent star burst has lighted up the Cartwheel rim which has a diameter larger than that of the Milky Way galaxy in which our planet exists. The Cartwheel Galaxy is a lenticular ring galaxy which is about 500 million light-years away. This galaxy was discovered by Fritz Zwicky in the year 1941.

So we can conclude that the ring shape of the Cartwheel Galaxy is due to collisions with another galaxy.

Learn more about galaxy here: brainly.com/question/13956361

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7 0
1 year ago
How many mols are present in the a sample of silver nitrate which has<br> 5.3x10^24 molecules.
Westkost [7]

Answer:  5.3 x 10^24 formula units of silver nitrate is equivalent to 8.8 moles of silver nitrate. Silver nitrate is an ionic compound, therefore, its representative particle is called a "formula unit" instead of molecule. For every mole of a substance, we know that there are 6.022 x 10^23 representative units of that substance. The amount of particles in one mole of substance is called Avogadro's number.

Further Explanation:

We can convert from number of representative particles to moles using the formula:

\boxed {no. \ of \ moles \ = \ ( given \ no. \ of \ particles) \ (\frac{1 \ mole}{\ 6.022 \ x 10^{23} particles})}

For this problem, we can calculate the number of moles by plugging in the given values to the equation above,

no. \ of \ moles \ = (5.3 \ x \ 10^{24} \ formula \ units \ AgNO_{3}) \ (\frac{1 \ mole \ AgNO_{3}}{6.022 \ x 10^{23} \ formula \ units AgNO_{3}}) \\\\\boxed {no. \ of moles \ AgNO_{3} \ = \ 8.8 \ moles}

Learn More

  1. Learn more about representative particles brainly.com/question/8969313
  2. Learn more about Avogadro's number brainly.com/question/229300
  3. Learn more about mole conversions brainly.com/question/1370888

Keywords: moles conversion, Avogadro's number

5 0
3 years ago
Ammonification is the formation of
Vesna [10]
Ammonification refers to chemical reactions in which amino groups (NH2) associated with organic forms of nitrogen are converted into ammonia (NH3) or ammonium (NH4+).
7 0
2 years ago
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