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IgorLugansk [536]
3 years ago
15

For a certain reaction A → products a plot of ln[A] vs. time produces a straight line with a slope of −3.0×10−2 s−1. Which of th

e following statements is or are true?: The reaction follows first-order kinetics. The rate constant for the reaction is 3.0×10−2 s−1. The initial concentration of [A] was 1.0 M. For a certain reaction a plot of ln[] vs. time produces a straight line with a slope of . Which of the following statements is or are true?: The reaction follows first-order kinetics. The rate constant for the reaction is . The initial concentration of [] was 1.0 . Only one of the statements is true Statements I and II are true Statements I and III are true Statements II and III are true All three statements are true
Chemistry
1 answer:
Zarrin [17]3 years ago
3 0

Answer:

Statements I and II are true.

Explanation:

Let us consider the reaction A → products.

Which of the following statements is or are true?

I. The reaction follows first-order kinetics. TRUE

The expression for a first-order reaction is:

ln[A] = ln[A]₀ - k.t    [1]

where,

[A] is the concentration of the reactant A at certain time t

[A]₀ is the initial concentration of A

k is the rate constant

t is the time

If the plot of ln[A] vs. t A is a straight line, it means that the reaction follows a first-order kinetics.

II. The rate constant for the reaction is 3.0×10⁻² s⁻¹. TRUE.

In [1], ln[A]₀ is the intercept and -k the slope of the linear equation. Thus,

-k = −3.0×10⁻² s⁻¹

k = 3.0×10⁻² s⁻¹

III. The initial concentration of [A] was 1.0 M. FALSE.

Since we do not have information about the intercept in the plot of ln[A] vs. t, we do not have enough information to calculate the initial concentration of A.

Statements I and II are true.

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<u>The </u><u>emperical formula </u><u>can be </u><u>calculated </u><u>as follows:</u>


<u>mass :</u>   4.12g of N            and        0.88g of H

<u>moles:</u>   4.12g/14.007       and        0.88g/1.008

               

<u>moles:</u>   0.294                   and        0.873


<u>moles/smallest number</u>:   (gives the ratio of atoms)


             0.294/0.294                and           0.873/0.294

                   1                               and             2.969

                    1                              and              3



The simplest ratio of N : H is 1 : 3

<u>Hence the </u><u>emperical formula </u><u>is </u><u>NH3</u>


<u>Explanation:</u>

 1.   The emperical formula can be found by getting  the <u>simplest ratio of atoms in a molecule.</u>

2. To get the simplest ratio of atoms we find out the <u>number of moles of each atoms in it.</u>

3. From the number of moles of atoms we can find the simplest ratio of each atom by dividing the <u>number of moles by the smallest number.</u>


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