1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
IgorLugansk [536]
3 years ago
15

For a certain reaction A → products a plot of ln[A] vs. time produces a straight line with a slope of −3.0×10−2 s−1. Which of th

e following statements is or are true?: The reaction follows first-order kinetics. The rate constant for the reaction is 3.0×10−2 s−1. The initial concentration of [A] was 1.0 M. For a certain reaction a plot of ln[] vs. time produces a straight line with a slope of . Which of the following statements is or are true?: The reaction follows first-order kinetics. The rate constant for the reaction is . The initial concentration of [] was 1.0 . Only one of the statements is true Statements I and II are true Statements I and III are true Statements II and III are true All three statements are true
Chemistry
1 answer:
Zarrin [17]3 years ago
3 0

Answer:

Statements I and II are true.

Explanation:

Let us consider the reaction A → products.

Which of the following statements is or are true?

I. The reaction follows first-order kinetics. TRUE

The expression for a first-order reaction is:

ln[A] = ln[A]₀ - k.t    [1]

where,

[A] is the concentration of the reactant A at certain time t

[A]₀ is the initial concentration of A

k is the rate constant

t is the time

If the plot of ln[A] vs. t A is a straight line, it means that the reaction follows a first-order kinetics.

II. The rate constant for the reaction is 3.0×10⁻² s⁻¹. TRUE.

In [1], ln[A]₀ is the intercept and -k the slope of the linear equation. Thus,

-k = −3.0×10⁻² s⁻¹

k = 3.0×10⁻² s⁻¹

III. The initial concentration of [A] was 1.0 M. FALSE.

Since we do not have information about the intercept in the plot of ln[A] vs. t, we do not have enough information to calculate the initial concentration of A.

Statements I and II are true.

You might be interested in
A sample of 23.2 g of nitrogen gas is reacted with
slavikrds [6]

Answer:

1.66 moles.

Explanation:

We'll begin by calculating the number of mole in 23.2 g of nitrogen gas, N2.

This is illustrated below:

Molar mass of N2 = 2x14 = 28 g/mol

Mass of N2 = 23.2 g

Mole of N2 =.?

Mole = mass /Molar mass

Mole of N2 = 23.2/28

Mole of N2 = 0.83 mole

Next, we shall determine the number of mole in 23.2 g of Hydrogen gas, H2.

This is illustrated below:

Molar mass of H2 = 2x1 = 2 g/mol

Mass of H2 = 23.2 g

Mole of H2 =?

Mole = mass /Molar mass

Mole of H2 = 23.2/2

Mole of H2 = 11.6 moles

Next, the balanced equation for the reaction. This is given below:

N2 + 3H2 —> 2NH3

From the balanced equation above,

1 mole of N2 reacted with 3 moles of H2 to produce 2 moles of NH3.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

1 mole of N2 reacted with 3 moles of H2.

Therefore, 0.83 moles will react with = (0.83 x 3) = 2.49 moles of H2.

From the calculations made above, we can see that only 2.49 moles out of 11.6 moles of H2 is required to react completely with 0.83 mole of N2.

Therefore, N2 is the limiting reactant.

Finally, we shall determine the maximum amount of NH3 produced from the reaction.

In this case, we shall use the limiting reactant because it will give the maximum yield of NH3 since all of it is consumed in the reaction.

The limiting reactant is N2 and the maximum amount of NH3 produced can be obtained as follow:

From the balanced equation above,

1 mole of N2 reacted to produce 2 moles of NH3.

Therefore, 0.83 mole of N2 will react to produce = (0.83 x 2) = 1.66 moles of NH3.

Therefore, the maximum amount of NH3 produced from the reaction is 1.66 moles.

5 0
3 years ago
a particular application calls for N2 g with a density of 1.80 g/L at 32 degrees C what must be the pressure of the n2 g in mill
baherus [9]

Answer:

1223.38 mmHg

Explanation:

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

Also,  

Moles = mass (m) / Molar mass (M)

Density (d)  = Mass (m) / Volume (V)

So, the ideal gas equation can be written as:

PM=dRT

Given that:-

d = 1.80 g/L

Temperature = 32 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (32 + 273.15) K = 305.15 K

Molar mass of nitrogen gas = 28 g/mol

Applying the equation as:

P × 28 g/mol  = 1.80 g/L × 62.3637 L.mmHg/K.mol × 305.15 K

⇒P = 1223.38 mmHg

<u>1223.38 mmHg must be the pressure of the nitrogen gas.</u>

5 0
3 years ago
Jumping on a cemented floor is more pain full than a sandy flour,why​
Anvisha [2.4K]

Answer:

Is soft

Explanation:

because concrete is hard ash so t hink flour would be safer

5 0
3 years ago
PLEASE HELP!!!!!!!!!
andreev551 [17]

The average atomic mass of the imaginary element : 47.255 amu

<h3>Further explanation  </h3>

The elements in nature have several types of isotopes  

Isotopes are elements that have the same Atomic Number (Proton)  

Atomic mass is the average atomic mass of all its isotopes  

Mass atom X = mass isotope 1 . % + mass isotope 2.% ..

isotope E-47 47.011 amu, 87.34%

isotope E-48 48.008 amu, 6.895

isotope E-49 50.009 amu, 5.77%

The average atomic mass :

\tt avg~mass=0.8734\times 47.011+0.06895\times 48.008+0.0577\times 50.009\\\\avg~mass=41.059+3.310+2.886\\\\avg~mass=47.255~amu

5 0
3 years ago
`You have to be careful about pouring drano down your pipes since it is mainly hydrochloric acid--you can't do it if they are ma
Zanzabum

Answer:

6.67 moles

Explanation:

Given that:-

Moles of hydrogen gas produced = 10.0 moles

According the reaction shown below:-

2Al + 6HCl\rightarrow 2AlCl_3 +3H_2

3 moles of hydrogen gas are produced when 2 moles of aluminium undergoes reaction.

Also,

1 mole of hydrogen gas are produced when \frac{2}{3} moles of aluminium undergoes reaction.

So,

10.0 moles of hydrogen gas are produced when \frac{2}{3}\times 10.0 moles of aluminium undergoes reaction.

<u>Moles of Al needed  = \frac{2}{3}\times 10.0 moles = 6.67 moles</u>

6 0
3 years ago
Other questions:
  • What is the frequency of a wave traveling at 5,000 m/s with a wavelength of .002 m/cycle?
    10·1 answer
  • To prepare the cooling system for an ice cream freezer, the chef adds 59.7 g of salt (NaCl) to 1433.3 g of ice. Predict the lowe
    15·1 answer
  • Sodium is produced by electrolysis of molten sodium chloride. what are the products at the anode and cathode, respectively?
    15·1 answer
  • If an atom has 17 protons and 18 neutrons, what is the charge of the atom's nucleus?​
    15·1 answer
  • For the reaction C6H14(g) ------&gt; C6H6(g) + 4H2(g), the rate of formation of hydrogen gas, H2 was found to be 2.5 x 10-2 atm/
    11·1 answer
  • Which property provides the best evidence that the unknown substance is a solid
    5·1 answer
  • How many moles are in 25 grams of HF
    7·2 answers
  • What is the definition of a radical​
    15·2 answers
  • Why are scientific models important in the study of science?
    13·1 answer
  • Which words help you to determine the meaning of the word declerate in paragraph 3 ?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!