Using kinematic equation, v^2 - u^2 = 2as. 5^2 - 3^2 = 2a x 16. a = 0.5m/s^2. So particle will deaccelerate at 0.5m/s^2. ( v = final velocity, u= initial velocity, a= acceleration, s= displacement.)
Explanation:
The given data is as follows.
radius (r) = 3.25 cm, 
Now, we will calculate the tangential acceleration as follows.
Putting the given values into the above formula as follows.
= 
= 37.7 
Thus, we can conclude that the tangential acceleration of a point on the rim of the flywheel during this spin-up process is 37.7 .
The best and most correct answer among the choices provided by your question is the second choice or letter b.
Ex is negative from x = -2 to x = 0, and positive from x = 0 to x = 2 <span>correctly describes the orientation of the x-component of the electric field along the x-axis.</span>
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Answer:period, spring constant, radius of circular part, velocity of the test mass, mass of the test-mass, mass of the hanging mass
Explanation:
