Answer:
0.085 moles of N₂O₅ are needed
Explanation:
Given data:
Mass of NO₂ produces = 7.90 g
Moles of N₂O₅ needed = ?
Solution:
2N₂O₅ → 4NO₂ + O₂
Number of moles of NO₂ produced :
Number of moles = mass/ molar mass
Number of moles = 7.90 g/ 46 g/mol
Number of moles = 0.17 mol
now we will compare the moles of NO₂ with N₂O₅.
NO₂ : N₂O₅
4 : 2
0.17 : 2/4×0.17 = 0.085 mol
Thus, 0.085 moles of N₂O₅ are needed.
The largest risks while designing a model to withstand a village include that the model does not mitigate the effects of the tsunami or only mitigates the effects partially, which would cause damages to the homes.
Designing a model to withstand the effect of any natural phenomenon such as an earthquake, fire or tsunami is not an easy task and will require the following cycle:
- Designing the model.
- Testing the model.
- Making changes or designing a new model.
In the case of a model for tsunamis, it is likely the following problems occur:
- The model does not protect the houses from tsunamis.
- The model does not protect the houses completely.
This would lead to negative effects such as:
- Damages in the houses.
- Dead or injured people.
- Destruction of infrastrcture.
Note: This question is incomplete because the context is missing; here is the missing part.
Protecting Your Model Village from Tsunamis this task, you will design a model village to withstand the effects of a tsunami.
Learn more about tsunami in: brainly.com/question/1126317
<h3>
Answer:</h3>
Distance traveled is 9.055 km
<h3>
Explanation:</h3>
Speed is given by dividing distance by time.
The distance given is 550 ft and the time is 100 seconds.
Therefore; Speed = 550 ft ÷ 100 sec
= 5.5 ft/sec
We can calculate the distance the runner covered in one and half hour.
Time = 1.5 hours
But 1 hour = 3600 sec
1.5 hours = (1.5 × 3600)
= 5400 sec
Distance is given by multiplying speed and time
Thus; Distance = 5.5 ft/sec × 5400 sec
= 29700 ft
But; 1 m = 3.28 ft
1000 m = 1 km
Therefore; 29700 ft will be equivalent to
= 29700 ft/3.28 ft
= 9054.878 M
but 1000 m = 1 km
Thus, distance = 9054.878 ÷ 1000 m
= 9.055 km
Concentration of Ni in 20mL = 5.28ppm x dilution factor = 5.28 x 100/5 = 105.6 ppm = 105.6 mg/L
molar mass of Ni = 58.6934 g
<span>Molarity of Ni = 100.40 x 10^{-3} / 58.6934 = 1.71 x 10^{-3} M = 1.71 mM. </span>
