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4 years ago

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A 6.26 g sample of a solid containing ni is dissolved in 20.0 ml water. a 5.00 ml aliquot of this solution is diluted to 100.0 m

l and analyzed in the lab. the solution was determined to contain 5.28 ppm ni. determine the molarity of ni in the 20.0 ml solution.

1 answer:

saveliy_v [14]4 years ago

5 0

Concentration of Ni in 20mL = 5.28ppm x dilution factor = 5.28 x 100/5 = 105.6 ppm = 105.6 mg/L

molar mass of Ni = 58.6934 g
<span>Molarity of Ni = 100.40 x 10^{-3} / 58.6934 = 1.71 x 10^{-3} M = 1.71 mM. </span>

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