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lukranit [14]
2 years ago
9

Calculate the concentration of the rubidium hydroxide solution in g dm³. (relative atomic mass: Rb = 85; relative formula mass:

RbOH = 102)
Chemistry
1 answer:
Fofino [41]2 years ago
5 0

Answer:

assalam o aalaikum

Explanation:

o

90

180

270

360 x

-1

Given that 0 find the value of a and the value of b.

(2 marks)

.

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Help its due soon i need to get this right to pass the class
Igoryamba

Answer:

the answer I am pretty sure is A

Explanation:

Because the way that a generator works is moving electric current around a wire and using magnets to make more energy. please tell me if I am wrong.

4 0
3 years ago
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Which is an example of an object increasing its kinetic energy
hodyreva [135]

Answer:

The answer to this question is the A choice. A rocket before launch.

Explanation:

In the definition of kinetic energy, it says: In physics, the kinetic energy of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes.

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2 years ago
What is the composition of 'Clean dry air'<br><br> - Idk what subject its just science
Luba_88 [7]
Dry air is a mixture of nitrogen, oxygen, carbon dioxide etc.
air is a mixture of gases 78% nitrogen an 21% oxygen and other components.
7 0
3 years ago
(06.04 HC)
Ksju [112]

The mass of sodium chloride at the two parts are mathematically given as

  • m=10,688.18g
  • mass of Nacl(m)=39.15g

<h3>What is the mass of sodium chloride that can react with the same volume of fluorine gas at STP?</h3>

Generally, the equation for ideal gas is mathematically given as

PV=nRT

Where the chemical equation is

F2 + 2NaCl → Cl2 + 2NaF

Therefore

1.50x15=m/M *(1.50*0.0821)

1-50 x 15=m/58.5 *(1.50*0.0821)

m=10,688.18g

Part 2

PV=m'/MRT

1*15=m'/58.5*0.0821*273

m'=39.15g

mass of Nacl(m)=m'=39.15g

Read more about Chemical Reaction

brainly.com/question/11231920

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7 0
2 years ago
What is the total number of atoms in 0.20 mol of propanone, CH3COCH3?
Nutka1998 [239]

Answer:

1.2×10²³ atoms.

Explanation:

Data obtained from the question include:

Mole of propanone = 0.20 mole

Number of atoms of propanone =.?

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.022×10²³ atoms.

This implies that 1 mole of propanone also contains 6.022×10²³ atoms.

Thus, we can obtain the number of atoms in 0.20 mole of propanone as illustrated below:

1 mole of propanone contains 6.022×10²³ atoms.

Therefore, 0.20 mole of propanone will contain = 0.2 × 6.022×10²³ = 1.2×10²³ atoms.

Thus, 0.20 mole of propanone contain

1.2×10²³ atoms.

6 0
3 years ago
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