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klio [65]
2 years ago
11

Calculate the poh of a solution at 25. 0 °C that contains 2. 95 × 10^-12 m hydronium ions.

Chemistry
1 answer:
lapo4ka [179]2 years ago
8 0

The pOH of a solution at 25. 0 °C that contains 2. 95 × 10^-12 M hydronium ions is 0.5.

pH is the concentration of the hydrogen ion released or gained by the species in the solution that depicts the acidity and basicity of the solution.

pOH is the concentration of the hydroxide ion in the solution and is dependent on the pH as an increase in pH decreases the pOH and vice versa.

Total H+ ions = 2.95 x 10⁻¹² M

pH is calculated as:

pH = -log[H+]

Substituting values in the equation:

log( 2.95 x 10⁻¹² M)= 13.5 pH

pOH is calculated as:

14 - pH = pOH

Substituting values in the equation above:

14 - 13.5 = 0.5 pOH

Therefore, pH is 13.5 and pOH is 0.5.

Learn more about pH and pOH here: brainly.com/question/2947041

#SPJ4

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Arrange the following substances in order of increasing solubility of water. C6H14, C6H13Br, C6H13OH, C6H12(OH)2.
Juli2301 [7.4K]

Answer:

C6H14 < C6H13Br  < C6H13OH < C6H12(OH)2

Explanation:

Hello,

In this case, since the solubility in water is related with the presence of polar bonds in the given molecules we can see that C6H12(OH)2 has the presence two O-H bonds which promote the highest solubility via hydrogen bonds as well as the C6H13OH but in a lower degree as only on O-H bond is present. Next since the bond C-Br in is slightly close to the polar bond C6H13Br rather than the C-C bonds only had by C6H14 we can infer that C6H13Br is more soluble in water than C6H14, therefore the required order is:

C6H14 < C6H13Br  < C6H13OH < C6H12(OH)2

Whereas C6H12(OH)2 is the most soluble and C6H14 the least soluble in water.

Best regards.

5 0
3 years ago
Use the information in the table about four different electric circuits to answer the question
ycow [4]

Answer:

Circuit 4

Explanation:

To know the correct answer to the question given above, we shall determine the current in each circuit. This can be obtained as follow:

For circuit 1:

Resistance (R) = 0.5 ohms

Voltage (V) = 20 V

Current (I) =?

V = IR

20 = I × 0.5

Divide both side by 0.5

I = 20 / 0.5

I = 40 A

For circuit 2:

Resistance (R) = 0.5 ohms

Voltage (V) = 40 V

Current (I) =?

V = IR

40 = I × 0.5

Divide both side by 0.5

I = 40 / 0.5

I = 80 A

For circuit 3:

Resistance (R) = 0.25 ohms

Voltage (V) = 40 V

Current (I) =?

V = IR

40 = I × 0.25

Divide both side by 0.25

I = 40 / 0.25

I = 160 A

For circuit 4:

Resistance (R) = 0.25 ohms

Voltage (V) = 60 V

Current (I) =?

V = IR

60 = I × 0.25

Divide both side by 0.25

I = 60 / 0.25

I = 240 A

SUMMARY

Circuit >>>>>> Current

1 >>>>>>>>>>> 40 A

2 >>>>>>>>>>> 80 A

3 >>>>>>>>>>> 160 A

4 >>>>>>>>>>> 240 A

From the above calculation, circuit 4 has the greatest electric current.

8 0
3 years ago
The following equation lnN - N₀ = -kt Of time t is plotted on x-axis and lnN is plotted on y-axis, what are the slopes and y-int
stepladder [879]

Answer:

-k slope

The term No is the y intercept(does not mean NO) y-intercept

Explanation:

For a straight line graph, the normal equation could be written as

y = mx + c

Where m is the slope and c is the y intercept.

Writing the equation is the form of y = mx + c gives the following;

lnN = -kt + No

As obtained from the question, t is plotted in the x-axis, while lnN is the plot on the y-axis.

Now, we are asked to obtain the slope and the y-intercept. It can be seen that the slope is the coefficient of the term x in this case t. Hence, our slope is -k.

The y-intercept is the other term which in this case is No

6 0
3 years ago
How does the ribosome know the sequence of amino acids
Andreyy89

Answer:

The ribosome contains three grooves which are sites for the tRNA. The first codon is AUG, which is called a "start codon". ... So, the tRNA that has the anti-codon sequence of UAC carrying the amino acid Met bonds to the mRNA codon. Another tRNA bonds to the next codon in the next groove with the next amino acid

7 0
3 years ago
The molar concentration of sucrose in a can of soda is 0.375 M. How much sucrose would be found in a 2 liter bottle of soda of t
antoniya [11.8K]

Answer:

C)  0.75 mol.

Explanation:

  • Molarity is defined as the no. of moles of solute dissolved in 1.0 L of the solution.

So, The molar concentration of sucrose in a can of soda is 0.375 M means that: every 1.0 L of sucrose contains 0.375 mol of sucrose.

∴ 2 liter bottle of soda of the same concentration contains (2 * 0.375 mol = 0.75 mol) of sucrose.

<em>Thus, the right choice is: C)  0.75 mol.</em>

5 0
3 years ago
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