Producers (autotroph)
I’m sorry if this isn’t the answer you were looking for, if so, please be more specific and I can try to help again, thank you.
Do length x width x height which is 10 cm x 8.2 cm and 3.5 cm. Pay close attention to sig figs as well (or if your teacher doesn't mind all that much then don't fret about it, but mine's really picky!)
Combustion equation of n-hexane:
2C₆H₁₄ + 19O₂ → 12CO₂ + 14H₂O
a)
Assuming we have 100 moles of air,
Oxygen = 20.9 moles
n-hexane required = 20.9/19 x 2
= 2.2 moles
LFL = Half of stoichometric amount = 2.2 / 2 = 1.1
LFL n-hexane = 1.1%
b)
1.1 volume percent required for LFL
1.1% x 1
= 0.0011 m³ of n-hexane required
Iron oxide is rust. So oil would be an inhibitor.
