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Tresset [83]
2 years ago
9

If the shape of the moon appears to be increasing over time, what is

Chemistry
2 answers:
Rom4ik [11]2 years ago
6 0
B hope that helps have a good one
Montano1993 [528]2 years ago
3 0

Answer:

B

Explanation:

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A student mixes a 10.0 ml sample of 1.0 m naoh(aq) with a 10.0 ml sample of 1.0 m hcl(aq) in a polystyrene container. the temper
AleksAgata [21]
Hrxn = Q reaction / mol of reaction
mol of reaction = M * V = 10 * 1 = 10 mmol = 0.01 mol
Q water = m * C * (Tf - Ti)
             = (10 + 10) (4.184) (26-20) = 502.08 J
Q reaction = - Q water = -502.08 J
Hrxn = -502.08 / (0.01) = - 50208 J = - 50.21 kJ/mol
5 0
2 years ago
A 3.0-mol sample of kclo3 was decomposed according to the equation 2kclo3(s) --> 2kcl(s) + 3o2(g) how many moles of o2 are fo
d1i1m1o1n [39]
2moles of O2 are formed.
5 0
2 years ago
How many grams of CO2 are used when 6.0 g of O2 are produced? Express your answer with the appropriate units.
Ipatiy [6.2K]

Answer:

that is why co2 is in the power of 2ik

8 0
3 years ago
Which of the following would not be considered an observation in terms of the scientific method?
prohojiy [21]

Answer:

the first option, tasting a pasta sauce after adding a new ingredient.

Explanation:

tasting a pasta sauce after adding a new ingredient is not an observation because there is no qualitative or quantitative data to be taken from that experience.

4 0
3 years ago
Alum is a compound used in a variety of applications including cosmetics, water purification, and as a food additive. It can be
mylen [45]

yield = 52.23 %

Explanation:

We have the following chemical reaction:

2 Al (s) + 2 KOH (aq) + 4 H₂SO₄ (aq) + 10 H₂O → 2 KAl(SO₄)₂·12 (H₂O) (s) + 3 H₂ (g)

mass of aluminium = mass of bottle with aluminium pieces - bottle mass

mass of aluminium = 10.8955 - 9.8981 = 0.9974 g

mass of alum = mass of bottle with final product - bottle mass

mass of alum = 19.0414 - 9.8981 = 9.1433 g

number of moles = mass / molecular weight

number of moles of aluminium = 0.9974 / 27 = 0.03694 moles

number of moles of alum (practical) = 9.1433 / 474 = 0.01929 moles

To calculate the theoretical quantity of alum that should be obtained from 0.03694 moles of aluminium we devise the following reasoning:

if       2 moles of aluminium produce 2 moles of alum

then 0.03694 moles of aluminium produce X moles of alum

X = (0.03694 × 2) / 2 = 0.03694 moles of alum (theoretical)

yield = (practical quantity / theoretical quantity) × 100

yield = (0.01929 /  0.03694) × 100

yield = 52.23 %

Learn more about:

reaction yield

brainly.com/question/7786567

#learnwithBrainly

5 0
3 years ago
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