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vichka [17]
2 years ago
9

Approximating the eye as a single thin lens 2. 70 cm from the retina, find the focal length of the eye when it is focused on an

object at a distance of 265 cm?
Physics
1 answer:
barxatty [35]2 years ago
7 0

The focal Length of the eye is 0.37cm.

The retina, which is always 2.70 cm away from the lens, serves as the image's primary imaging medium. Image distance is 2.70 cm as a result.

The object is located 265 cm away from the eye's lens.

Based on lens formula:

\frac{1}{f} = \frac{1}{u} + \frac{1}{v}

where the object distance is u, the image distance is v, and the focal length is f.

Consequently, u is 265.00 cm and v is 2.70 cm.

\frac{1}{f} = \frac{1}{265} + \frac{27}{10}

\frac{1}{f} = \frac{7165}{2650}

f = \frac{2650}{7165}

f = 0.37

Thus, the focal length of the eye is 0.37cm.

Learn more about focal length here;

brainly.com/question/13885819

#SPJ4

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A cylinder containing an ideal gas has a volume of 2.6 m3 and a pressure of 1.5 × 105 Pa at a temperature of 300 K. The cylinder
frozen [14]
<h2>Answer:13.5\times 10^{8} joules</h2>

Explanation:

From the first law of thermodynamics,

ΔQ=ΔU+W

Where Q is the heat given to the gas,

U is the internal energy of the gas,

W is the workdone by the gas.

When pressure is constant,

\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}

V_{2}=\frac{2.6\times 900}{300}=7.8m^{3}

When pressure is constant,W=PΔV

Where P is pressure and V is the volume of the gas.

Given P=1.5\times 10^{5}Pa

ΔV=7.8-2.6=5.2m^{3}

So,W=1.5\times 10^{5}\times 5.2=7.8\times 10^{5}J

Given that ΔU=6\times 10^{5}

So,ΔQ=6\times 10^{5}+7.8\times 10^{5}=13.8\times 10^{5}J

5 0
4 years ago
A 49.5-turn circular coil of radius 5.10 cm can be oriented in any direction in a uniform magnetic field having a magnitude of 0
ipn [44]

Answer:

The magnitude of the maximum possible torque exerted on the coil is 5.73 x 10⁻³ Nm

Explanation:

Given;

number of turns of the circular coil, N = 49.5 turns

radius of the coil, r = 5.10 cm = 0.051 m

magnitude of the magnetic field, B = 0.535 T

current in the coil, I = 26.5 mA = 0.0265 A

The magnitude of the maximum possible torque exerted on the coil is calculated as;

τ = NIAB

where;

A is the area of the coil

A = πr² = π(0.051)² = 0.00817 m²

Substitute the given values and solve for the maximum torque

τ = (49.5) x (0.0265) x (0.00817) x (0.535)

τ = 0.00573 Nm

τ = 5.73 x 10⁻³ Nm

3 0
3 years ago
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The correct option is <u>D</u>.

Qualitative observations are observations that are made using our senses of sight, hearing, smell, taste and feel. These observations do not involve numbers or measurements of any kind.

The student's observations regarding the squirrel as is mentioned in options A, B and C involve measurements. Therefore these are not qualitative observations.

Option D, however, is made on the basis of sight, where the student observes the squirrel moving in a zigzag manner.

Therefore, of all the three observations, the student's observation that the squirrel ran in a zigzag pattern is the qualitative observation.

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3 Points Ricardo is going to take a flight from New York, New York, to Memphis, Tennessee. The flight leaves New York at 10:15 a
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