1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ziro4ka [17]
3 years ago
9

A sample of gold has a mass of 38.6 grams and a volume of 2 cm3 what is the density of gold

Physics
2 answers:
Contact [7]3 years ago
7 0

Answer:

Density, d=19.3\ g/cm^3

Explanation:

Mass of the sample of gold, m = 38.6 grams

Volume of gold sample, V=2\ cm^3

The density of gold sample is given by mass per unit volume. Mathematically, it is given by :

d=\dfrac{m}{V}

d=\dfrac{38.6\ g}{2\ cm^3}

d=19.3\ g/cm^3

So, the density of the sample of gold is 19.3\ g/cm^3. Hence, this is the required solution.

Rudik [331]3 years ago
3 0
Density = Mass ÷ Volume

Your mass = 38.6 grams
Your volume = 2 cm3

38.6 ÷ 2 = 19.3 grams per cm3
You might be interested in
A bag of sugar weighs 2 kg on earth. What should it weigh in newtons on the moon, where the free-fall acceleration is 1/6 that o
Elis [28]
<span> Weight = mass x acceleration
Earths acceleration is 9.8 m/s*2
1 kg = 2.2 lbs, so 2.0 lbs x 1 kg/2.2 lbs = 0.91 kg
The bag would have a weight of 9.8 x 0.91 = 8.9 N

1. 8.9 x 1/6 = 1.5 N

2. 8.9 x 2.64 = 23.5 N

The mass of the bag at all three locations is 0.91 kg. Mass does not change, the different locations only change its weight. </span>
5 0
3 years ago
Which of the following is false
musickatia [10]

what are the options??

please include all of your question

4 0
3 years ago
Read 2 more answers
Is the term used to describe the removal of sand and soil by the wind.
Hitman42 [59]

Answer:

erosion

Explanation:

5 0
3 years ago
How to find i1, i2,i3
MrRissso [65]

to find i1, i2, and i3 we need to find the total current.

to find the total current, you need to find the total resistance

you're already given the total voltage, Vs

to find Rtotal, start from the resistors furthest from the voltage source.

R3 and R4 are in series so

Rtotal= R3+R4 = 6+3 = 9 ohms

9 ohms is now in parallel with R2 so,

Rtotal= (\frac{1}{R3+R4}) ^{-1}\\ + (\frac{1}{R2}) ^{-1})^-1= (1/18)^-1 +( 1/9)^-1 = 6 ohms

6 ohms is in series with R1 so

Rtotal=  4+6=10 ohms

itotal= (\frac{Vtotal}{Rtotal})

= 120 v/10 ohms = 12 A

i total = i1 because all the current flows through it

i1= 12A

so the current splits into i2 and i3 and the amount of current that flows through a branch depends on the total resistance in each branch.

we already calculated the resistance in the R3+R4 & R2 branch as 6 ohms

since r3 and r4 are in series, the same current will flow through them

r3+r4 = 9 ohms

r2= 18 ohms

so the current in r2 will be half that of R3 & R4 (V=IR)

using the current divider rule

Ix = Itotal * \frac{Rtotal}{Rx}

i2= 12A x (6 ohms/18 ohms)= 4 A

i3= 12A x (6 ohms/9 ohms) = 8 ohms

6 0
3 years ago
One billiard ball is shot east at 2.2 m/s. A second, identical billiard ball is shot west at 0.80 m/s. The balls have a glancing
Leona [35]

Answer:

(a). The speed of the first ball after the collision is 1.95 m/s.

(b). The direction of the first ball after the collision is 44.16° due south of east.

Explanation:

Given that,

Velocity of one ball u₁= 2.2i m/s

Velocity of second ball u₂=- 0.80i m/s

Final velocity of the second ball v₂= 1.36j m/s

The mass of the identical balls are

m = m_{1}=m_{2}

(a). We need to calculate the speed of the first ball after the collision

Using law of conservation of momentum

m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}

Along X- axis

m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}

v_{1}=u_{1}+u_{2}

Put the value into the formula

v_{1}=2.2i-0.80i

v_{1}=1.4i\ m/s

Along Y-axis

0=m_{1}v_{1}+m_{2}v_{2}

m_{1}v_{1}=-m_{2}v_{2}

v_{1}=-v_{2}

Put the value into the formula

v_{1}=-1.36j\ m/s

Then the final speed of the first ball

v_{1}=\sqrt{(1.4)^2+(1.36)^2}

v_{1}=1.95\ m/s

(b) We need to calculate the direction of the first ball after the collision

Using formula of direction

\tan\theta=\dfrac{v_{2}}{v_{1}}

\tan\theta=\dfrac{-1.36}{1.4}

\theta=\tan^{-1}\dfrac{-1.36}{1.4}

\theta=-44.16^{\circ}

Negative sign shows the direction of first ball .

Hence, (a). The speed of the first ball after the collision is 1.95 m/s.

(b). The direction of the first ball after the collision is 44.16° due south of east.

7 0
3 years ago
Other questions:
  • Which set of equipment would be most useful to determine the density of a liquid?
    9·1 answer
  • The gage pressure of an automobile tire is measured to be 210kPa before a trip and 220kPa after the trip at a location where the
    10·1 answer
  • Question 1 (1 point)
    11·1 answer
  • Select the statement that correctly completes the description of phase difference.
    5·1 answer
  • Consider a spherical Gaussian surface and three charges: q1 = 1.60 μC , q2 = -2.61 μC , and q3 = 3.67 μC . Find the electric flu
    13·1 answer
  • The graph represents velocity over time. What is the acceleration? –0.4 m/s2 –0.2 m/s2 0.2 m/s2 0.4 m/s2
    13·2 answers
  • The rate of change in position at a given point in time
    9·1 answer
  • Confirm that the force field F is conservative in some open connected region containing the points P and Q, and then find the wo
    6·1 answer
  • 1. The potential difference between the terminals a cell in open circuit is 2.2volt. With resistance of 5ohm across the terminal
    9·1 answer
  • A 20 kg rover is located on Mars where the acceleration due to gravity is 3.7 m/s/s.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!