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victus00 [196]
2 years ago
14

If the temperature rises by 9. 9 degrees, what is the corresponding temperature increase in degrees celsius?

Physics
1 answer:
Yanka [14]2 years ago
7 0

Main Answer:

Assume that the temperature rises by 9.9 F

Initial Temperatures will be C1, F1

Final temperatures will be C2, F1 + 9.9

The relation between celsius and fahrenheit temperature is as follows:

C = 5/9(F - 32)

Increase in temperature in celsius will be

C2 - C1 = F2 - F1

C2 - C1 = 5/9 ( F1 +9.9 -32) - 5/9 ( F1 -32)

C2 - C1 = 5/9 ( F1 +9.9 -32 - F1 +32)

C2 - C1 = 5/9 (9.9)

C2 - C1 = 5.5C

Explanation:

What is temperature?

Temperature is defined as the degree of coldness or hotness of an object or a substance. Generally, it is measured in various temperature scales. They are celsius, fahrenheit, kelvin.

To know more about temperature, please visit:

brainly.com/question/25677592

#SPJ4

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A flat coil of wire consisting of 20 turns, each with an area of 50 cm2, is positioned perpendicularly to a uniform magnetic fie
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Answer:

Induced current, I = 0.5 A

Explanation:

It is given that,

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Time taken, t = 2 s

Resistance of the coil, R = 0.4 ohms

We know that due to change in magnetic field and emf will be induced in the coil. Its formula is given by :

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Where

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\epsilon=NA\dfrac{B_f-B_i}{t}

\epsilon=20\times 0.005\times \dfrac{6-2}{2}

\epsilon=0.2\ V

Let I is the induced current in the wire. It can be calculated using Ohm's law as :

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I = 0.5 A

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3 years ago
Chapter 38, Problem 001
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Answer:

a) \lambda=2.95x10^{-6}m

b) infrared region

Explanation:

Photon energy is the "energy carried by a single photon. This amount of energy is directly proportional to the photon's electromagnetic frequency and is inversely proportional to the wavelength. If we have higher the photon's frequency then we have higher its energy. Equivalently, with longer the photon's wavelength, we have lower energy".

Part a

Is provide that the smallest amount of energy that is needed to dissociate a molecule of a material on this case 0.42eV. We know that the energy of the photon is equal to:

E=hf

Where h is the Planck's Constant. By the other hand the know that c=f\lambda and if we solve for f we have:

f=\frac{c}{\lambda}

If we replace the last equation into the E formula we got:

E=h\frac{c}{\lambda}

And if we solve for \lambda we got:

\lambda =\frac{hc}{E}

Using the value of the constant h=4.136x10^{-15} eVs we have this:

\lambda=\frac{4.136x10^{15}eVs (3x10^8 \frac{m}{s})}{0.42eV}=2.95x10^{-6}m

\lambda=2.95x10^{-6}m

Part b

If we see the figure attached, with the red arrow, the value for the wavelenght obtained from part a) is on the infrared region, since is in the order of 10^{-6}m

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Mr. Fuller assigned his science class a lab comparing the masses of objects to the nearest gram using a balance. The mass of a p
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Mekhanik [1.2K]

<u>Answer:</u>

Things become hot and cold because of the transfer of energy.

<u>Explanation:</u>

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