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Nata [24]
3 years ago
6

Which change will always result in an increase in the gravitational force between two objects?

Physics
1 answer:
Sunny_sXe [5.5K]3 years ago
4 0

Answer:

Increasing the masses of the objects and decreasing the distance between the objects.

Explanation:

Gravitational force always act between two objects that have mass. The gravitational force is a weak force and attractive in nature.

The force of pull depends on the masses of the two objects and the distance between them.

The formula to calculate gravitational force between two objects having masses 'm' and 'M' and separated by a distance 'd' is given as:

F_g=\frac{GmM}{d^2}

Where, 'G' is called the universal gravitational constant.

Now, from the above formula, it is clear that, the force of gravitation is inversely proportional to the square of the distance between the two objects and directly proportional to the masses of the two objects.

This means that, if masses increase with other parameters constant, force will increase and vice-versa. If distance decreases with other parameters constant, force will increase and vice-versa.

So, on combining the above two relations,we are certain that if one increases the masses and decrease the distance between, the gravitational force will definitely increase.

So, the third option is correct.

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Calculate the work against gravity required to build the right circular cone of height 4 m and base of radius 1.2 m out of a lig
Nana76 [90]

Answer:

Work done = 35467.278 J

Explanation:

Given:

Height of the cone = 4m

radius (r) of the cone = 1.2m

Density of the cone = 600kg/m³

Acceleration due to gravity, g = 9.8 m/s²

Now,

The total mass of the cone (m) = Density of the cone × volume of the cone

Volume of the cone = \frac{1}{3}\pi r^2 h

thus,

volume of the cone = \frac{1}{3}\pi 1.2^2\times 4 = 6.03 m³

therefore, the mass of the cone = 600 Kg/m³ × 6.03 m³ = 3619.11 kg

The center of mass for the cone lies at the \frac{1}{4}times the total height

thus,

center of mass lies at,  h' = \frac{1}{4}\times4=1m

Now, the work gone (W) against gravity is given as:

W = mgh'

W = 3619.11kg × 9.8 m/s² × 1 = 35467.278 J

4 0
3 years ago
What is the resistance of a 3.5 m copper wire (Rho= 1.7x10-8 Ohm·m) that 1 point
VikaD [51]

Answer:

(D)

Explanation:

Given :

l=3.5 m

A=5.26*10^{-6} m^{2}

p=1.7*10^{-8}  ohm.m

Resistance can be calculated as :

R=p\frac{l}{A} \\R=1.7*10^{-8} \frac{3.5}{5.26*10^{-6} }

R=\frac{5.95*10^{-2} }{5.26} \\R=1.13*10^{-2}

Resistance of the wire will be 1.1×10^{-2} ohms

Option D is correct

4 0
2 years ago
A newly discovered particle, the SPARTYON, has a mass 945 times that of an electron. If a SPARTYON at rest absorbs an anti-SPART
Gennadij [26K]

Answer:

\nu =1166\times 10^{20}Hz  

Explanation:

We have given the rest mass of SPARTYON = 945 times of mass of electron

We know that mass of electron =9.11\times 10^{-31}kg

So mass of SPARTYON =945\times 9.11\times 10^{-31}=8608.95\times 10^{-31}kg

Speed of light c=3\times 10^8m/sec

According to Einstein equation energy is given by

E=mc^2=8608.95\times 10^{-31}\times (3\times 10^{8})^2=77480.55\times 10^{-15}j

Now according to planks's rule

Energy is given by

E=h\nu , here h is plank's constant h=6.6\times 10^{-34}

So 77480.55\times 10^{-15}=6.6\times 10^{-34}\nu

\nu =1166\times 10^{20}Hz  

3 0
3 years ago
Please help this is really important thanks
Juliette [100K]
1. Giga is the largest
2. Stem-and-leaf
6 0
3 years ago
If the work required to move a 0.35 c charge from point a to point b is 125 j, what is the potential difference between the two
valentina_108 [34]
Using W = qV  =>  V = W/q


7 0
3 years ago
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