All categories

3 years ago

What is Maria’s hypothesis for the experiment? State why Maria think this is a good hypothesis

Physics

1 answer:

BartSMP [9]3 years ago

5 0

Answer:

Hot water will take longer to freeze into solid ice cubes than cold water, because the hot water molecules have to slow down more than cold water molecules to enter the solid state and become ice. ... All “cold” water must be at the same i

Explanation:

You might be interested in

All of the following are regulated by the medulla except __________.

Lelechka [254]

Answer:

i think its B sorry if its wrong

7 0

3 years ago

Read 2 more answers

1. What types of gas was the first atmosphere made out of?

sergij07 [2.7K]

17. a sea breeze is a breeze blowing towards the land
18. a land breeze is a breeze blowing towards the sea

8 0

3 years ago

Read 2 more answers

Help ASAP

SIZIF [17.4K]

I think all of those are examples

4 0

3 years ago

A solid cylindrical object has a mass of 2.0 kg, a diameter

omeli [17]

Answer:

I = 0.0025 kg.m²

Explanation:

Given that

m= 2 kg

Diameter ,d= 0.1 m

Radius , $R=\dfrac{d}{2}$

$R=\dfrac{0.1}{2}$

R=0.05 m

The moment of inertia of the cylinder about it's axis same as the disc and it is given as

$I=\dfrac{mR^2}{2}$

Now by putting the all values

$I=\dfrac{2\times 0.05^2}{2}$

I = 0.0025 kg.m²

Therefore we can say that the moment of inertia of the cylinder will be 0.0025 kg.m².

4 0

3 years ago

Copper has a modulus of elasticity of 110 GPa. A specimen of copper having a rectangular cross section 15.2 mm × 19.1 mm is pull

bearhunter [10]

Answer:

$strain = 1.4 \times 10^{-3}$

Explanation:

As we know by the formula of elasticity that

$E = \frac{stress}{strain}$

now we have

$E = 110 GPA$

$E = 110 \times 10^9 Pa$

Area = 15.2 mm x 19.1 mm

$A = 290.3 \times 10^{-6}$

now we also know that force is given as

$F = 44500 N$

here we have

stress = Force / Area

$stress = \frac{44500}{290.3 \times 10^{-6}}$

$stress = 1.53 \times 10^8 N/m^2$

now from above formula we have

$strain = \frac{stress}{E}$

$strain = \frac{1.53 \times 10^8}{110 \times 10^9}$

$strain = 1.4 \times 10^{-3}$

7 0

3 years ago