Answer:
BaBr2 + H2O
Explanation:
The equation is that of neutralization
2HBr + Ba(OH)2 =BaBr2 + H2O
Answer:
Oxidation Number of Phosphorous = + 6
Explanation:
According to Rules of Assigning Oxidation States;
i) The Oxidation State of Hydrogen atom in a compound is assigned as +1 except for Hydrides i.e. NaH and MgH₂ where it is assigned with -1.
ii) The Oxidation State of Oxygen in a compound is assigned as -2 except for Peroxides where it is given -1 and OF₂ where it is assigned with +1 respectively.
Oxidation State of P in H₂P₃O₁₀;
As over all molecule is neutral we can write it as,
H₂P₃O₁₀ = 0
Putting oxidation number of H and O,
(+1)₂ + P₃ + (-2)₁₀ = 0
(+2) + P₃ + (-20) = 0
+ 2 + (P)3 -20 = 0
(P)3 = + 20 - 2
(P)3 = + 18
P = + 18 ÷ 3
P = + 6
Answer:
Explanation:
Hello,
In this case, for a concentration of 0.42 M of benzoic acid whose Ka is 6.3x10⁻⁵ in 0.33 M sodium benzoate, we use the Henderson-Hasselbach equation to compute the required pH:
![pH=pKa+log(\frac{[base]}{[acid]} )](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%28%5Cfrac%7B%5Bbase%5D%7D%7B%5Bacid%5D%7D%20%29)
Whereas the concentration of the base is 0.33 M and the concentration of the acid is 0.42 M, thereby, we obtain:
![pH=-log(Ka)+log(\frac{[base]}{[acid]} )\\\\pH=-log(6.3x10^{-5})+log(\frac{0.33M}{0.42M} )\\\\pH=4.1](https://tex.z-dn.net/?f=pH%3D-log%28Ka%29%2Blog%28%5Cfrac%7B%5Bbase%5D%7D%7B%5Bacid%5D%7D%20%29%5C%5C%5C%5CpH%3D-log%286.3x10%5E%7B-5%7D%29%2Blog%28%5Cfrac%7B0.33M%7D%7B0.42M%7D%20%29%5C%5C%5C%5CpH%3D4.1)
Regards.
Explanation:
in this question, we're asked how to determine whether we have a metallic or nonmetallic substance.So what you want to do is one to remember that metals are malleable and Nonmetal are brittle. So if we were to hammer the metal, it would be very malleable, but the nonmetal would fall apart. And never we could just hammer the sample and see whether it was malleable. And therefore it would be a medal or a brittle and therefore being nonmetal.
