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Illusion [34]
2 years ago
14

Identify the most likely reaction product(s) in the monobromination of 2-pentanone by bromine in the presence of acid in the dar

k
Chemistry
1 answer:
irinina [24]2 years ago
7 0

The most likely reaction product in the monobromination of 2-pentanone by bromine in the presence of acid in the dark is known to be 1-Bromo-2-pentanone

<h3>What is a Monobromination?</h3>

The term is known to be the bringing in of one bromine atom into  what we call an organic compound.

Note that the brominating of benzene is known to be a good example of what we know as electrophilic aromatic substitution reaction. In this kind of reaction, the electrophile (which is bromine) is said to forms a kind of sigma bond to that of the benzene ring, bringing in an intermediate. Then, a proton is said to be deleted from the intermediate to create a substituted of benzene ring.

Hence, The most likely reaction product in the monobromination of 2-pentanone by bromine in the presence of acid in the dark is known to be 1-Bromo-2-pentanone

Learn more about monobromination from

brainly.com/question/14356147

#SPJ1

See full question below

Identify the most likely reaction product(s) in the monobromination of 2-pentanone by bromine in the presence of acid in the dark.

a.) 1-Bromo-2-pentanone and 3-bromo-2-pentanone

b.) 1-Bromo-2-pentanone, 3-bromo-2-pentanone, and 4-bromo-2-pentanone

c.) 1-Bromo-2-pentanone, 3-bromo-2-pentanone, 4-bromo-2-pentanone, and 5-bromo-2-pentanone

d.) 3-Bromo-2-pentanone

e.)1-Bromo-2-pentanone

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How many moles are in 8.30x10^23 molecules of H2o
LUCKY_DIMON [66]
You multiply avogadro's number to what you were given.
8.30x10^23 * 6. 0221409x10^23
=1.357*10^25

That should be the right answer but I'm not sure. It has been awhile since I have done this.

4 0
3 years ago
Read 2 more answers
How many particles are in 23 g of H 2 O?
Sedaia [141]
1 mole of any substance contains 6.022 × 1023 particles.

⚛ 6.022 × 1023 is known as the Avogadro Number or Avogadro Constant and is given the symbol NA

N = n × NA

· N = number of particles in the substance

· n = amount of substance in moles (mol)

· NA = Avogardro Number = 6.022 × 10^23 particles mol-1


For H2O we have:

2 H at 1.0 each = 2.0 amu
1 O at 16.0 each = 16.0 amu
Total for H2O = 18.0 amu, or grams/mole

It takes 18 grams of H2O to obtain 1 mole, or 6.02 x 1023 molecules of water. Think about that before we answer the question. We have 25.0 grams of water, so we have more than one mole of water molecules. To find the exact number, divide the available mass (25.0g) by the molar mass (18.0g/mole). Watch how the units work out. The grams cancel and moles moves to the top, leaving moles of water. [g/(g/mole) = moles].

Here we have 25.0 g/(18.0g/mole) = 1.39 moles water (3 sig figs).

Multiply 1.39 moles times the definition of a mole to arrive at the actual number of water molecules:

1.39 (moles water) * 6.02 x 1023 molecules water/(mole water) = 8.36 x 1023 molecules water.

That's slightly above Avogadro's number, which is what we expected. Keeping the units in the calculations is annoying, I know, but it helps guide the operations and if you wind up with the unit desired, there is a good chance you've done the problem correctly.

N = n × (6.022 × 10^23)


1 grams H2O is equal to 0.055508435061792 mol.

Then 23 g of H2O is 1.2767 mol


To calculate the number of particles, N, in a substance:

N = n × NA

N = 1.2767 × (6.022 × 10^23)

N= 176.26

N=
3 0
2 years ago
The characteristics of two different types of reactions are shown downwards
a_sh-v [17]

Answer:

Valence electrons are involved in Reaction B but not in Reaction A.

Explanation:

The description of reaction A in which protons are lost or gained by the atom of the element is a nuclear reaction. In nuclear reactions, the nucleons which are the protons and neutrons drives the reaction. No valence electrons in the orbiting shells are involved in this kind of reaction. During this type of reaction, an atom changes it identity to that of another.

Reaction B in which no identity change occurs is a chemical reaction. In chemical reactions bonds are formed by the atoms using the valence electrons that orbits round the central nucleus. The atoms remain the same but it chose to attain stability and an inert configuration by losing or gaining electrons.

4 0
3 years ago
Read 2 more answers
How many unpaired electrons are present in a ground-state atom from each of the following groups?
musickatia [10]

For 7A(17) :

Electronic configuration ns^2 np^5

So, there are 5 unpaired electrons present in group 7A(17).

<h3>What are Unpaired Electrons?</h3>
  • An unpaired electron is an electron that doesn't form part of an electron pair when it occupies an atom's orbital in chemistry.
  • Each of an atom's three atomic orbitals, designated by the quantum numbers n, l, and m, has the capacity to hold a pair of two electrons with opposing spins.
  • Unpaired electrons are extremely uncommon in chemistry because an object carrying an unpaired electron is typically quite reactive. This is because the production of electron pairs, whether in the form of a chemical bond or as a lone pair, is frequently energetically advantageous.
  • They play a crucial role in describing reaction pathways even though they normally only appear momentarily during a reaction on a thing called a radical in organic chemistry.

To learn more about unpaired electrons with the given link

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6 0
2 years ago
Calculează cantitatea de zahăr (C12 H22 O11) în ceaiul de dimineața dacă o linguriță conține 5g de zahăr?
slavikrds [6]

Answer:

Explanation:

Translated:

Calculate the amount of sugar (C12 H22 O11) in the morning tea if a teaspoon contains 5g of sugar?

Given parameters

Mass of sugar = 5g

Unknown:

Amount of the sugar =?

Solution:

A mole is the amount of substance that contains avogadro's number of particles i.e 6.02 x 10²³

Therefore, to find the number of moles contained in the teaspoon of sugar we use the expression below:

    Number of moles = \frac{mass}{molar mass}

Molar mass of C₁₂H₂₂O₁₁ = (12x12) + (1x22) + (16x11) = 342g/mol

    Number of moles = \frac{5}{342} = 0.015mol of sugar

or 0.015 x 6.02 x 10²³, 8.8x10²¹atoms of sugar

8 0
4 years ago
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