3.5 moles of a gas will occupy 2.7 L at 1.5 atm at a temperature of 14.1K
IDEAL GAS LAW:
- The temperature of a gas can be calculated using the ideal gas law equation:
PV = nRT
Where;
- P = pressure (atm)
- V = volume (L)
- n = number of moles (mol)
- R = gas law constant (0.0821 Latm/molK)
- T = temperature (K)
- According to this question, P = 1.5atm, V = 2.7L, n = 3.5moles, T = ?
- 1.5 × 2.7 = 3.5 × 0.0821 × T
- Therefore, 3.5 moles of a gas will occupy 2.7 L at 1.5 atm at a temperature of 14.1K
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Answer:
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Explanation:
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Answer:
The proper matching is given below.
Explanation:
a Separate molecules by size size exclusion chromatography
b Separate molecules by charge Ion exchange chromatography
c The stationary phase has a covalently bound group to which a protein in the mobile phase can bind. Affinity chromatography
d uses mobile phase and stationary phase to separate protein Size exclusion chromatography
e The stationary phase contain cross linked polymers with different pore size
Size exclusion chromatography
f can separate molecules based on protein ligand binding Affinity chromatography
g The stationary phase may contain negatively or positively charged groups
ion exchange chromatography
The 3rd option is the answer
Answer:
D
Explanation:
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