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3 years ago

14

Convert the shorthand structure of tyrosine to a complete structure with all atoms and lone pairs drawn in. Tyrosine is one of t

he 20 amino acids used for protein synthesis.

1 answer:

Vikentia [17]3 years ago

8 0

Answer:

no

Explanation:

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Calculate the solubility of carbon dioxide at 400 kPa.

BaLLatris [955]

The solubility of carbon dioxide at 400 kPa at room temperature is ;

( B ) 0.61 CO2/L

<u>Given data </u>

pressure of CO₂ = 400 Kpa = 3.95 atm

Kh of CO₂ = 3.3 * 10⁻² mol/L.atm

<h3>Calculate the solubility of carbon dioxide </h3>

Solubility = pressure * Kh value of CO₂

= 3.95 atm * 3.3 * 10⁻² mol / L.atm

= 0.13 mol/l CO₂

= 0.61 CO₂ / L

Hence we can conclude that the solubility of CO₂ at 400 kPa is 0.13 mol/l CO₂.

Learn more about solubility : brainly.com/question/23946616

From the options the closest answer is ( B ) 0.61 CO₂ / L

7 0

2 years ago

Consider a voltaic cell where the anode half-reaction is Zn(s) → Zn2+(aq) + 2 e− and the cathode half-reaction is Sn2+(aq) + 2 e

notsponge [240]

<u>Answer:</u> The concentration of $Sn^{2+}$ in the cell is $9.0\times 10^{-3}M$

<u>Explanation:</u>

We are given:

<u>Oxidation half reaction:</u> $Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-$ $E^o_{Zn^{2+}/Zn}=-0.76V$

<u>Reduction half reaction:</u> $Sn^{2+}(aq.)+2e^-\rightarrow Sn(s)$ $E^o_{Sn^{2+}/Sn}=-0.136V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Here, tin will undergo reduction reaction and will get reduced.

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=-0.136-(-0.76)=0.624V$

To calculate the EMF of the cell, we use the Nernst equation, which is:

$E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Mn^{2+}]}{[Cu^{2+}]}$

where,

$E_{cell}$ = electrode potential of the cell = 0.660 V

$E^o_{cell}$ = standard electrode potential of the cell = +0.624 V

n = number of electrons exchanged = 2

$[Zn^{2+}]=2.5\times 10^{-3}M$

$[Sn^{2+}]$ = ?

Putting values in above equation, we get:

$0.660=0.624-\frac{0.059}{2}\times \log(\frac{2.5\times 10^{-3}}{[Sn^{2+}})$

$[Sn^{2+}]=9.0\times 10^{-3}M$

Hence, the concentration of $Sn^{2+}$ ions is $9.0\times 10^{-3}M$

3 0

3 years ago

Why do nitrogen and oxygen form negative ions, not positive ones, in simple binary compounds.

gavmur [86]

Answer:

it is easier for them to have an octet of electrons(8e)

Each ion will: obtain the noble gas structure, each atom has high ionization energy

Explanation:

.

5 0

2 years ago

The extraction of pure copper is expensive. Give one reason why

goblinko [34]

Because it requires lots of electricity to turn it into an aqueous solution so that electrolysis can be performed on it.

3 0

3 years ago

Read 2 more answers

4) The most electronegative atom of the ones listed below is ____.AlBTlInGa

marusya05 [52]

Answer:

$B$

Explanation:

Here, we wnat to get the most electronegative atom

On the periodic table, electronegativity increases across a period and decrease down the group

The elements listed are in the same group

Boron is the first member of the group

Boron is the most electronegative atom in the group

5 0

1 year ago