Answer:
1.26 g of Cu
Explanation:
Since we have to find the percentage of the given amount so...
Yield in grams = (Initial mass used / 100) x Percentage Yield
Yield in grams = (1.57 / 100) x 80.6 = 1.26 g of Cu
Energy = Planck's constant * Frequency
E = (6.62607004 × 10⁻³⁴<span>) * 7 * 10</span>¹⁴
E = 46.38 * 10⁻²⁰
E = 4.638 * 10⁻¹⁹ J
Hope this helps!
Answer: A volume of .5650 what? And what unit will be considered?
Answer: It is a basic solution with pH =8.51
Explanation:
We were given that hydroxide ion concentration [OH-] as 3.26 x 10-6 M
But We know thar
[OH-] [H+] = 1 × 10^-14
To get the Hydrogen ion [H+] concentration, we have that
[H+] = 1 × 10^-14 M/[OH-]
= 1 × 10^-14 M/3.26 x 10-6 M
= 3.067 x 10^-9 M
But, pH = - log [H+]
Therefore,
pH = - log (3.067 x 10^-9)
pH=8.51
when pH > 7, The solution is basic, therefore a solution with pH =8.51 is basic.
I Cant Answer your question but maybe this will help
Volume Changes for Gases
Particles in a gas have more freedom of movement than they do in a liquid. According to the ideal gas law, the pressure (P) and volume (V) of a gas are mutually dependent on temperature (T) and the number of moles of gas present (n). The ideal gas equation is PV = nRT, where R is a constant known as the ideal gas constant. In SI (metric) units, the value of this constant is 8.314 joules ÷ mole - degree K.
Pressure is constant: Rearranging this equation to isolate volume, you get: V = nRT ÷ P, and if you keep the pressure and number of moles constant, you have a direct relationship between volume and temperature: ∆V = nR∆T ÷ P, where ∆V is change in volume and ∆T is change in temperature. If you start from an initial temperature T0 and pressure V0 and want to know the volume at a new temperature T1 the equation becomes:
V1 = [n • R • (T1 - T0) ÷ P] +V0
Temperature is constant: If you keep the temperature constant and allow pressure to change, this equation gives you a direct relationship between volume and pressure:
V1 = [n • R • T ÷ (P1 - P0)] + V0
Notice that the volume is larger if T1 is larger than T0 but smaller if P1 is larger than P0.
Pressure and temperature both vary: When both temperature and pressure vary, the the equation becomes:
V1 = n • R • (T1 - T0) ÷ (P1 - P0) + V0
Plug in the values for initial and final temperature and pressure and the value for initial volume to find the new volume.
