The amount of Na₂SO₄ would be 15.09 grams
<h3>Stoichiometric calculation</h3>
From the equation of the reaction:
4NaOH + 2H₂SO₄ --> 2Na₂SO₄ + 4H₂O
Mole ratio of NaOH and Na₂SO₄ = 2:1
Mole of 8.50 grams of NaOH = 8.50/40
= 0.21 mole
Equivalent mole of Na₂SO₄ = 0.21/2
= 0.11 mole
Mass of 0.11 mole Na₂SO₄ = 0.11 x 142.04
= 15.09 grams
More on stoichiometric reactions can be found here: brainly.com/question/8062886
Answer:
See explanation
Explanation:
Iron exhibits two stable oxidation states, +2 and +3 states. The difference between FeO and Fe2O3 is that, in FeO, Fe is in the +2 oxidation state while in Fe2O3, Fe is in the +3 oxidation state
In FeO, iron looses two electrons which are gained by oxygen as follows;
Fe^2+ + O^2- -----> FeO
In Fe2O3, Fe looses six electrons while oxygen has gained six electrons as shown;
2Fe^3+ + 3O^2- ------>Fe2O3
The mass of one mole of Neon is equal to the molar mass depicted on the periodic table. This is <span>20.1797 g.</span>
